Calculating Armature Current from Active & Reactive Power & Voltage

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Discussion Overview

The discussion revolves around calculating the armature current of a permanent magnet DC motor supplied by a single-phase, full-wave controlled bridge rectifier, given the active power, reactive power, and voltage. The context includes theoretical and practical considerations regarding power consumption and current calculations in electrical systems.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant asks how to calculate the armature current using active power (1200W), reactive power (1000VAR), and a 240V AC voltage source.
  • Another participant suggests calculating the RMS active and reactive currents using the formulas: RMS Active Current = Active Power / RMS Voltage and RMS Reactive Current = Reactive Power / RMS Voltage.
  • A participant questions the implications of the reactive power consumption, suggesting it may be due to a capacitor filter, and asserts that the DC motor does not consume reactive power during steady state.
  • Another participant argues that motor windings consume reactive power to develop magnetic fields, which contradicts the previous claim regarding the DC motor's operation.
  • One participant proposes finding the apparent power using the relationship S^2 = P^2 + Q^2 to solve for current, and questions the use of "sqrt3" in the formula for current, clarifying that it is a single-phase system.
  • A later reply emphasizes that the calculated current will only represent the RMS current on the AC side and discusses the assumptions regarding the current waveform on the DC side.

Areas of Agreement / Disagreement

Participants express differing views on whether the DC motor consumes reactive power, leading to a lack of consensus on the role of reactive power in this context. The discussion remains unresolved regarding the implications of reactive power in the operation of the DC motor.

Contextual Notes

There are assumptions about the motor's operation and the impact of reactive power that are not fully explored, including the effects of the capacitor filter and the nature of the current waveform.

ramox3
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How do calculate the current when I have the active power and reactive power and voltage?

A single-phase, full-wave controlled bridge rectifier supplies a permanent magnet dc motor. The rectifier is connected to a 240V ac voltage source and absorbs 1200W of active power and 1000VAR of reactive power from the source. If power loss in the rectifier is negligible how do i calucalte the armature current?
 
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RMS Active Current = Active Power / (RMS Voltage)
RMS Reactive Current = Reactive Power / (RMS Voltage)
 


so what can I say about the value of the current in the armature?
 


I am unsure of what might be consuming the reactive power, perhaps the capacitor Filter you might be using. I don't think DC motor Consume any reactive power during Steady State. So, going with that, all the active power is being consumed by the DC motor.
And the Current Going into it (i.e. into the armature) Depends on whether you are using Capacitor and what size. Assuming you are using Large Sized Capacitor so that the Terminal Voltage Across the Motor is almost constant near the peak of 240*Sqrt(2), then the Current into the armature is
Armature Current = 12000 / (339) = 3.53 A
 


the motor windings are coils they consume reactive power to develop magnetic fields
 


find apparent power with real and reactive then use that to solve for current.

S^2 = root P^2 + Q^2

I = S/root3 V ?
 


FOIWATER said:
the motor windings are coils they consume reactive power to develop magnetic fields
I don't think that's the case for DC motor. Since, they can even overate on Pure DC, there is no way they can consume reactive Power, which occurs only in AC.
 


FOIWATER said:
find apparent power with real and reactive then use that to solve for current.

S^2 = root P^2 + Q^2

I = S/root3 V ?

There is no "sqrt3" as this is a single phase bridge, but otherwise you are correct. But remember that that will only calculate the RMS current on the AC side. If you know the shape of the current waveform however, then from this you can deduce the average current on the DC side.

Lacking any other details, this type of question usually assumes that the current on the DC side is approximately constant due to the motor inductance, so that the line current is a square wave. Given this assumption you can actually calculate both the DC current and the (phase control) firing angle from the given data.
 
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