Calculating Average Force: Momentum Question

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To calculate the average force between a baseball and bat, the change in momentum must be determined using the change in velocity, which is 91 m/s. The initial calculation of 1.89 kg*m/s was incorrect because it did not account for the direction change of the ball. The correct average force, factoring in the change in velocity and the contact time of 0.001 seconds, is 13,200 N. The importance of considering direction in momentum calculations is emphasized. Accurate calculations require attention to both magnitude and direction of velocity changes.
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This seems like an easy question.
A 0.145 kg baseball pitched at 39.0 m/s is hit on a horizontal line drive straight back toward the pitcher at 52.0 m/s. If the contact time between the bat and ball is 0.001 seconds, calculate the average force between the ball and bat during contact.

I used Average Force= change in momentum divided by change in time.
I figured the change in momentum to be 1.89 kg*m/s and change in time to be .001 seconds. Dividing, I got 1,890 N. The answer given by the textbook is 13,200 N.
 
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HINT: The change in velocity is 91 m/s.
 
you need to use the change in velocity. make sure to take the directions into account.

edit:

tide beat me to it! =p
 
Gotta be quick, Andrew! ;)
 
That's right, i forgot velocity was changing directions. Thank you.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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