Calculating Average Force in Nonelastic Collisions with No External Forces

  • Thread starter Thread starter nhmockus
  • Start date Start date
  • Tags Tags
    Impulse Momentum
Click For Summary

Homework Help Overview

The discussion revolves around calculating the average force during a nonelastic collision involving a baseball and a bat, with specific focus on the velocities before and after impact and the time of contact. The problem is situated within the context of mechanics, particularly impulse and momentum principles.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formula for average force in the context of nonelastic collisions and question the correct interpretation of initial and final velocities. There is an exploration of the direction of velocity changes and how they affect calculations.

Discussion Status

The conversation is ongoing, with participants clarifying the values used in calculations and questioning the assumptions about velocity direction. Some guidance is being offered regarding the interpretation of velocity changes, but no consensus has been reached.

Contextual Notes

There is a focus on the implications of directionality in velocity changes, with participants considering whether the change in velocity could be negative based on the motion described.

nhmockus
Messages
5
Reaction score
0
A 0.145-kg baseball pitched at 35.0m/s is hit on a horizontal line drive straight back toward the pitcher at 57.0 m/s.
If the contact time between bat and ball is 2.50×10−3s , calculate the average force between the ball and bat during contact.

The equation has something to do with nonelastic collisions but it has no external forces so it should have something like m*(v(f)-v(i)/change in t

I tried to plug and chug but it wasn't correct. ((57-22)*.145)/(2.5*(10^-3) The answer I came out with was 1276
 
Physics news on Phys.org
nhmockus said:
((57-22)*.145)/(2.5*(10^-3)

Where did the 22 come from?
 
Haha that's what i found. Sorry, it should be 57-35 to = 22. I did it correctly in my calculations
 
nhmockus said:
Haha that's what i found. Sorry, it should be 57-35 to = 22. I did it correctly in my calculations

Think about which direction the velocity is going in, are you sure the change in velocity is 57-35=22?
 
Why wouldn't it be? Or are you saying that it could be negative?
 
If I am traveling east at 5m/s, then I turn around and start traveling west at 3m/s, what is the change in my velocity?
 

Similar threads

Magnitude of the average force during a collision
  • · Replies 2 ·
Replies
2
Views
7K
Calculate Impulse and average force
  • · Replies 10 ·
Replies
10
Views
4K
Average force exerted on a baseball
  • · Replies 3 ·
Replies
3
Views
2K
Work done during a collision -- Change in Kinetic Energy & change in Momentum
  • · Replies 1 ·
Replies
1
Views
2K
Average force between baseball and bat
  • · Replies 3 ·
Replies
3
Views
3K
How Is Impulse Calculated in a Baseball Pitch?
  • · Replies 6 ·
Replies
6
Views
7K
Average force and angle, collision problem
  • · Replies 23 ·
Replies
23
Views
3K
Average force on a baseball when struck by a bat
  • · Replies 2 ·
Replies
2
Views
3K
Calculating Average Force for a Baseball Batting Exercise
  • · Replies 2 ·
Replies
2
Views
3K
Making Momentum Chart and Finding Force for Baseball and Bat
  • · Replies 3 ·
Replies
3
Views
2K