Need help with momentum related questions

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Homework Help Overview

The discussion revolves around a problem involving momentum and average force applied by a bat to a baseball. The scenario includes a baseball with a mass of 0.25 kg, initially pitched at 40 m/s, which is struck by a bat, reversing its direction and increasing its speed to 45 m/s. The contact time between the bat and the ball is given as 0.006 seconds.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of impulse and change in momentum to find the average force. There is a suggestion to verify the answer using kinetic energy and time, prompting questions about the validity of using energy in this context.

Discussion Status

Some participants have provided guidance on the correct approach to calculating average force, emphasizing the relationship between momentum and force. There is acknowledgment of the confusion regarding the use of energy in the calculation, with a distinction made between different formulations of force.

Contextual Notes

Participants note that the problem specifies the time of force application rather than distance, which is a point of clarification in the discussion. There is also mention of common misconceptions regarding average force calculations in educational contexts.

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kenny243 said:
A bat strikes a 0.25 kg baseball pitched at 40 m/s. The bat reverses the ball’s direction and gives it a speed of 45 m/s. What average force does the bat apply to the ball if they are in contact for 0.006 s?
I got 3542.67J.

I used Impulse=change in momentum.
F(0.006s)=0.25kg(45m/s-(-40ms))

Did I do it right?
 
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kenny243 said:
A bat strikes a 0.25 kg baseball pitched at 40 m/s. The bat reverses the ball’s direction and gives it a speed of 45 m/s. What average force does the bat apply to the ball if they are in contact for 0.006 s?
I got 3542.67J.

I used Impulse=change in momentum.
F(0.006s)=0.25kg(45m/s-(-40ms))

Did I do it right?

Welcome to the PF.

In the future, please use the Homework Help Template that you are provided when you start a new thread in the HH forums. It helps to organize the post into sections to make it easier for us to help you. :-)

To check your answer, you could calculate the average force a second way. Can you do it using the change in the kinetic energy and the time? Show us your work on that, and see if you get the same answer...
 
berkeman said:
Can you do it using the change in the kinetic energy and the time?
Not that I can see. Bear in mind that average force is ##\vec {\Delta p}/\Delta t##. Energy doesn't really enter into it.
kenny243 said:
Did I do it right?
Yes.
 
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I think I see why now. They give the time that the force was applied, not the distance. Thanks haruspex! :-)
 
berkeman said:
I think I see why now. They give the time that the force was applied, not the distance. Thanks haruspex! :)
There's a bit more to it than that. As I posted, average force is ##\vec{\Delta p}/\Delta t##, not ##\Delta E/\Delta s##. Using the latter formulation would lead to the bizarre result that the average force might be different from mass times average acceleration. They do give the same result when the force is constant, but rarely otherwise. Besides, taking the vector equation ##\vec F.\vec{ds} = dE## and dividing through by ds is not really on.
Sadly, questions from textbooks and teachers asking for average force given energy and distance are a regular occurrence on this forum. I do my best to enlighten the students that this is not actually valid, hoping that some will able to pass this on to their elders.
 
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