Calculating Average Force on a Ball Hitting a Hard Surface

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SUMMARY

The discussion centers on calculating the average force exerted by a hard surface on a ball weighing 10g that impacts the surface at a speed of 5m/s and rebounds with the same speed. The correct formula used is F = M(v2 - v1) / t, where M is the mass in kilograms, v2 is the final velocity, v1 is the initial velocity, and t is the time of contact. The user initially miscalculated the average force as 5N but corrected their understanding to realize that the change in velocity should account for both the impact and rebound, resulting in an average force of 100N.

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Homework Statement


A ball weighing 10g hit s ahard surface vertically with a speed of 5m/s and rebounds with the same speed.The ball remains in contact with the surface for 0.01 sec. The average force exerteed by the surface on the ball is :a) 100N b)10N c)1N d) 0.1N

Homework Equations

The Attempt at a Solution


using F= M(v2-v1)/t. I subs the values and converted g to kg.I also took the initial velocity as 5m/s and final as zero, time =0.01 sec . But I am getting 5 N. Where is my understanding flawed?
 
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takando12 said:
rebounds with the same speed

takando12 said:
final as zero
Compare those two statements.
 
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oh...initial and final are same. 5-(-5)=10. Stupid me.Thank you sir.
 

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