A very hard rubber ball (m = 0.2 kg) is falling vertically at 3 m/s just before it bounces on the floor. The ball rebounds back at essentially the same speed. If the collision with the floor lasts 0.05 s, what is the average force exerted by the floor on the ball?
Net force= change in momentum/ time taken
Linear momentum= mass x velocity
The Attempt at a Solution
I found the linear momentum of the ball before it hits the ground: .2 kg x 3 m/s= .6
After this I am lost and am not sure what I do next. I not sure what I need to do in order to find average force from this information.