Average Acceleration Calculation for Ball Bouncing off a Tennis Racket

Click For Summary

Homework Help Overview

The problem involves calculating the average acceleration of a ball that bounces off a tennis racket, with initial and final velocities provided. The ball's initial speed is 3 m/s, and after bouncing, it returns at 2 m/s, with a contact time of 12 ms.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of average acceleration using the formula a = (Vf - Vi) / (Tf - Ti) and express concerns about the sign of the acceleration. There is a focus on the direction of velocities before and after the bounce.

Discussion Status

Participants are actively engaging in clarifying the assumptions regarding the direction of velocities and how they affect the calculation of acceleration. Some have provided calculations, while others are questioning the implications of negative acceleration and the definition of positive direction in the context of the problem.

Contextual Notes

There is a lack of explicit information regarding which direction is defined as positive in the problem statement, leading to varied interpretations among participants.

DracoMalfoy
Messages
88
Reaction score
4

Homework Statement


A ball is traveling at 3m/s then bounces off of a tennis racket and returns at 2m/s. If the ball is in contact with the racket for 12ms, what is the average acceleration?

Homework Equations


average acceleration and conversion

a=Vf-Vi/Tf-Ti
1s= 1000ms

The Attempt at a Solution


Before I started, I converted 12ms to s and got 0.012s. I know the equation for avg acceleration. but I feel like I'm missing a step. I plug in the numbers and get an unrealistic solution. The answer comes out negative. I feel like I am missing something. Or I am making it too complicated for myself.
 
Physics news on Phys.org
Please show your actual steps. Dont just say ”I put in the numbers and think I got it wrong”. How on Earth are we to see if you got it wrong or not if you don't show us what you did?
 
DracoMalfoy said:

Homework Statement


A ball is traveling at 3m/s then bounces off of a tennis racket and returns at 2m/s. If the ball is in contact with the racket for 12ms, what is the average acceleration?

Homework Equations


average acceleration and conversion

a=Vf-Vi/Tf-Ti
1s= 1000ms

The Attempt at a Solution


Before I started, I converted 12ms to s and got 0.012s. I know the equation for avg acceleration. but I feel like I'm missing a step. I plug in the numbers and get an unrealistic solution. The answer comes out negative. I feel like I am missing something. Or I am making it too complicated for myself.
Everything you have showed us so far looks correct. A negative acceleration is not necessarily wrong. The magnitude of the acceleration should be pretty large to cause that change in velocity in such a short time. Why don't you show us your calculations so we can see if they are correct?
 
Orodruin said:
Please show your actual steps. Dont just say ”I put in the numbers and think I got it wrong”. How on Earth are we to see if you got it wrong or not if you don't show us what you did?

I subtracted 2m/s from 3m/s and then divided by the time 0.012s.
 
tnich said:
Everything you have showed us so far looks correct. A negative acceleration is not necessarily wrong. The magnitude of the acceleration should be pretty large to cause that change in velocity in such a short time. Why don't you show us your calculations so we can see if they are correct?

I subtracted 2m/s from 3m/s and then divided by the time 0.012s and got -83.3m/s^2 :olduhh:
 
DracoMalfoy said:
I subtracted 2m/s from 3m/s and then divided by the time 0.012s and got -83.3m/s^2 :olduhh:
Velocity has direction. The change in speed 1m/s, but what is the change in velocity?
 
DracoMalfoy said:
I subtracted 2m/s from 3m/s and then divided by the time 0.012s and got -83.3m/s^2 :olduhh:
You need to think about which direction the ball is traveling in before and after hitting it with the racket. Does the sign of the velocity change?
 
tnich said:
You need to think about which direction the ball is traveling in before and after hitting it with the racket. Does the sign of the velocity change?

I'm guessing that after it hits the racket it goes in the opposite direction so should 2m/s be negative?
 
DracoMalfoy said:
I'm guessing that after it hits the racket it goes in the opposite direction so should 2m/s be negative?
Yes.
 
  • #10
haruspex said:
Yes.

Okay. I changed that. So i subtracted 3m/s from -2m/s and got -5. Then I divided by 0.012s and got -417m/s^2. but the question is multiple choice. The answers are:

A) 0.417m/s^2
B) -56m/s^2
C) 0m/s^2
D) 83.3m/s^2
E) 417m/s^2
 
  • #11
DracoMalfoy said:
Okay. I changed that. So i subtracted 3m/s from -2m/s and got -5. Then I divided by 0.012s and got -417m/s^2. but the question is multiple choice. The answers are:

A) 0.417m/s^2
B) -56m/s^2
C) 0m/s^2
D) 83.3m/s^2
E) 417m/s^2
Which direction is positive in your answer? Which direction is positive in the multiple choice answers?
 
  • #12
tnich said:
Which direction is positive in your answer? Which direction is positive in the multiple choice answers?

3m/s is the positive direction. 2m/s is the negative direction I'm assuming since its returning. B is the only negative answer though :H
 
  • #13
Does the sign depend on which direction you define as negative and which you define as positive? Is it specified in the problem which is the positive direction?
 
  • #14
Orodruin said:
Does the sign depend on which direction you define as negative and which you define as positive? Is it specified in the problem which is the positive direction?

Now that I really think about it... I see the ball traveling FROM the wall or whatever is projecting it to the racket and back in the other direction... but the problem doesn't state which is the negative direction.
 
  • #15
DracoMalfoy said:
Now that I really think about it... I see the ball traveling FROM the wall or whatever is projecting it to the racket and back in the other direction... but the problem doesn't state which is the negative direction.
Then which answer can be correct knowing that the people who constructed the problem may have defined the positive direction in either direction?
 
  • #16
Orodruin said:
Then which answer can be correct knowing that the people who constructed the problem may have defined the positive direction in either direction?

417m/s^2? E? I first thought D) 83.3m/s^2 but that was incorrect.
 
  • #17
DracoMalfoy said:
417m/s^2? E?
Yes.
 

Similar threads

Replies
5
Views
6K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 11 ·
Replies
11
Views
2K