Calculating average inflation rate per year

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ainster31
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Homework Statement



An economist has predicted that for the next 5 years, annual inflation will be 8%, and then there will be 5 years at a 6% inflation rate. This is equivalent to what average price change per year for the entire 10-year period?

Homework Equations


The Attempt at a Solution



This is the solution given:

To buy $1 worth of goods today will require:
F = P (F/P, f%, n) n years hence.
F = $1 (1 + 0.08)5 = $1.47 5 years hence.

For the subsequent 5 years the amount required will increase to:
$1.47 (F/P, f%, n) = $1.47 (1 + 0.06)5 = $1.97

Thus for the ten year period $1 must be increased to $1.97. The average price change per year is:
($1.97 - $1.00)/10 yrs = 9.7% per year

Isn't this wrong? You can't just divide the average price change per year because it compounds, right?

I've tried verifying the answer and it appears wrong to me:

$$F=$1(1+0.097)^{ 10 }\\ F=$2.52$$

which is not equal to the $1.97 we were expecting.
 
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The OP states that the inflation rate is 8% for the first 5 years, and then the rate drops to 6% for the next 5 years. These were not the numbers used in your calculations.
 
Yeah, it seems the textbook messed that up too. I've corrected the numbers.
 
ainster31 said:

Homework Statement



An economist has predicted that for the next 5 years, annual inflation will be 8%, and then there will be 5 years at a 6% inflation rate. This is equivalent to what average price change per year for the entire 10-year period?

Homework Equations





The Attempt at a Solution



This is the solution given:

To buy $1 worth of goods today will require:
F = P (F/P, f%, n) n years hence.
F = $1 (1 + 0.08)5 = $1.47 5 years hence.

For the subsequent 5 years the amount required will increase to:
$1.47 (F/P, f%, n) = $1.47 (1 + 0.06)5 = $1.97

Thus for the ten year period $1 must be increased to $1.97. The average price change per year is:
($1.97 - $1.00)/10 yrs = 9.7% per year

Isn't this wrong? You can't just divide the average price change per year because it compounds, right?

I've tried verifying the answer and it appears wrong to me:

$$F=$1(1+0.097)^{ 10 }\\ F=$2.52$$

which is not equal to the $1.97 we were expecting.

Why are you using an 'arithmetic' average (0.97/10) in a problem having 'geometric' growth?
 
Ray Vickson said:
Why are you using an 'arithmetic' average (0.97/10) in a problem having 'geometric' growth?

Yeah, this textbook is terrible. It has way too many errors. I'm not sure how high these authors were when they wrote this textbook:

Donald G. Newnan is Professor Emeritus of Industrial and Systems Engineering at San Jose State University.

Ted G. Eschenbach is a consultant and Professor Emeritus of Engineering Management at the University of Alaska Anchorage.

Jerome P. Lavelle is Associate Dean in the College of Engineering at North Carolina State University.
 
Yes, it's quite obvious that the answer must be between 6% and 8%. In fact, because the two periods are the same there's a very easy shortcut.
 
Chestermiller said:
Try [itex](1+i)^{10}=1.97[/itex]
More simply, (1+i)2 = 1.06*1.08.