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Calculating average power using impedance and rms current

  1. May 17, 2013 #1
    1. The problem statement, all variables and given/known data

    Calculate the average power (P) absorbed by the load shown below when its impedance is 56 +j15 ohms 21 A rms?
    Answer to three significant figures

    2. Relevant equations

    P=Irms^2*R


    3. The attempt at a solution

    Converting 56 +j15 to polar form yields 57.9741 ohms @ 14.9951 degrees
    So 21^2*57.9741 = 25.5kW
     
  2. jcsd
  3. May 17, 2013 #2

    rude man

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    Homework Helper
    Gold Member

    "Load shown below"??

    Anyway,
    What is the power dissipated in the j15 ohm inductor?

    Should you be including it in your power dissipation calculation? You had the right formula!
     
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