Calculating average power using impedance and rms current

[pokie_panda]

Homework Statement

Calculate the average power (P) absorbed by the load shown below when its impedance is 56 +j15 ohms 21 A rms?
Answer to three significant figures

Homework Equations

P=Irms^2*R

The Attempt at a Solution

Converting 56 +j15 to polar form yields 57.9741 ohms @ 14.9951 degrees
So 21^2*57.9741 = 25.5kW

 

[rude man]

Homework Statement

Calculate the average power (P) absorbed by the load shown below when its impedance is 56 +j15 ohms 21 A rms?
Answer to three significant figures

Homework Equations

P=Irms^2*R

The Attempt at a Solution

Converting 56 +j15 to polar form yields 57.9741 ohms @ 14.9951 degrees
So 21^2*57.9741 = 25.5kW

"Load shown below"??

Anyway,
What is the power dissipated in the j15 ohm inductor?

Should you be including it in your power dissipation calculation? You had the right formula!