1. The problem statement, all variables and given/known data Referencing the attached picture: a) Show that the RMS current in the 1 kΩ resistor is 6.5mA. b) If the AC voltage source was replaced by a battery, what would the current in the resistor be? 2. Relevant equations V = IR Z = √(R^2 + X^2) 3. The attempt at a solution To begin, I calculated the impedance of the inductor and the capacitor, as well as the inductor and resistor. From these I found ZL&C = 1528.72Ω, and ZL&R = 843.56Ω. Next (and this is where I think I may have gone wrong), I added the values of these impedances together to find ZTotal = 2372.28Ω. Rearranging Ohm's Law, I find that IRMS = 4.2 mA, which I assume can't be correct since I'm supposed to show that the current through the resistor is 6.5 mA. I assume I've made an error in calculating my impedance values, but after verifying with other online sources, I can't seem to find where my mistake is coming from. Any insight would be greatly appreciated.