- #1

KokoDaSilvaback

- 7

- 0

## Homework Statement

Referencing the attached picture:

a) Show that the RMS current in the 1 kΩ resistor is 6.5mA.

b) If the AC voltage source was replaced by a battery, what would the current in the resistor be?

## Homework Equations

V = IR

Z = √(R^2 + X^2)

## The Attempt at a Solution

To begin, I calculated the impedance of the inductor and the capacitor, as well as the inductor and resistor. From these I found Z

_{L&C}= 1528.72Ω, and Z

_{L&R}= 843.56Ω.

Next (and this is where I think I may have gone wrong), I added the values of these impedances together to find Z

_{Total}= 2372.28Ω.

Rearranging Ohm's Law, I find that I

_{RMS}= 4.2 mA, which I assume can't be correct since I'm supposed to show that the current through the resistor is 6.5 mA. I assume I've made an error in calculating my impedance values, but after verifying with other online sources, I can't seem to find where my mistake is coming from. Any insight would be greatly appreciated.