Calculating Average Speed from Lap 1 & 2

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NettioB
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Homework Statement



Hi

I read a question recently on the British Mensa website and I thought the answer was 112.5mph. The answer given was 108mph. What is the calculation for this scenario?

"Lap 1 is completed at 135mph, lap 2 is completed at 90mph, what’s the average speed?"



Homework Equations



summation and division of two numbers


The Attempt at a Solution



135 plus 90 equals 225. 225 divided by 2 eqals 112.5


Thanks.

N.
 
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NettioB said:
So? Can you do the calculation as I indicated? It requires a little bit of algebra or the realization that is question is entirely analogous to finding the equivalent resistance of two resistors in parallel or the equivalent capacitance of two capacitors in series.
 
With this information I cannot. We only have two average speeds, one per lap (or two constant speeds, one per lap). We have neither a distance or a time.
 
NettioB said:
We have neither a distance or a time.
Neither of these are needed. Just the knowledge that the laps are of equal length. Start writing something down and see what develops.

Step 1. Can you write an equation for the definition of the average speed that I gave you? Use symbols for quantities that you don't know and have faith that it will all come out in the wash.
 
If L = lap distance and T1 and T2 = time to travel each lap, we can write:

Average speed = 4L / (T1 + T2)

But I can't get further than this.
 
t1 = v1 / L

t2 = v2 / L

Vavg = 2L2 / (v1 + v2)

= 2L2 / (135 + 90)

= L2 / 112.5


Where can I go from here?