Calculating Average Thrust Force for Airplane Take-off

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SUMMARY

The discussion focuses on calculating the average thrust force required for an airplane to take off, given a take-off speed of 250 mi/h and a weight of 110,000 Kg. The weight force is calculated using the formula F = mW, resulting in an average thrust force of 1,079,100 N (or 1079 kN). Participants express confusion over the relevance of the take-off speed and the clarity of the question, noting that the question is poorly worded and lacks necessary details for a complete solution.

PREREQUISITES
  • Understanding of Newton's laws of motion (F = ma)
  • Knowledge of weight calculation (W = mg) using gravitational acceleration
  • Familiarity with units of measurement, specifically converting miles per hour to meters per second
  • Basic principles of physics related to aircraft dynamics and take-off mechanics
NEXT STEPS
  • Research the conversion of miles per hour to meters per second for accurate calculations
  • Study the principles of thrust and drag in aviation physics
  • Learn about the role of runway length in take-off performance calculations
  • Explore recommended physics textbooks for deeper understanding of mechanics
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Aerospace engineering students, physics learners, and anyone interested in understanding the mechanics of airplane take-off and thrust calculations.

BlueOwl
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Homework Statement



The take-off speed of a given airplane is 250 mi/h. If the take-off weight is 110,000 Kg, what is average the thrust force exerted by the engines?


Homework Equations



w=mg ,F=ma , F=mW

The Attempt at a Solution



the mi/h confuses me and I don't know which formula to use and is the average thrust force the net force?
 
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mi/h is miles per hour. Think of it as distance/time, ie, velocity.

W(eight) is a force; it is your mass multiplied by the acceleration of the body you are standing on. On this case it is earth; so acceleration due to g(ravity) = 9.81 m/s.

I hope it is clear then that the Weight force F = mW of the aircraft is

9.81 * 110000 = 1,079,100 N, or 1079 kN.

Which I am pretty sure must be the answer...but to be honest the question is rather poorly written. Is that how it appears at in the textbook/whatever? Planes don't take off vertically because of the horizontal force applied by the Engines, as you probably well already know...

Let me know if there's anything you didn't get or would like clearing up:)
 
rabbitweed said:
mi/h is miles per hour. Think of it as distance/time, ie, velocity.

W(eight) is a force; it is your mass multiplied by the acceleration of the body you are standing on. On this case it is earth; so acceleration due to g(ravity) = 9.81 m/s.

I hope it is clear then that the Weight force F = mW of the aircraft is

9.81 * 110000 = 1,079,100 N, or 1079 kN.

Which I am pretty sure must be the answer...but to be honest the question is rather poorly written. Is that how it appears at in the textbook/whatever? Planes don't take off vertically because of the horizontal force applied by the Engines, as you probably well already know...

Let me know if there's anything you didn't get or would like clearing up:)

where does the 250 miles per hour come into the formula though? or it doesn't ?
 
I suspect that you left out some info? Perhaps the length of the runway?

And this certainly is a poorly worded question. For instance, kg is a unit of mass, not weight. If this is verbatim out of your physics book, then I feel sorry for you, and I hope we can be of some service.
 
BlueOwl said:
where does the 250 miles per hour come into the formula though? or it doesn't ?

It doesn't seem to at all. This is rather common in physics questions; give you quantities you don't need to confuse you. But with that question it really is hard to tell what on Earth they're asking.

Can I ask; are you doing this for school, or self-study? If the latter I'd be happy to recommend a good textbook.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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