Calculating Baud Rate for Analog Signaling

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SUMMARY

The baud rate for a channel using analog signaling with 4 different phase shifts and 8 different amplitudes at a bit rate of 100 Kbits/s is calculated based on the total number of symbols. With 32 unique symbols (4 phase shifts multiplied by 8 amplitudes), the baud rate is definitively 3,125 baud, derived from dividing the bit rate (100,000 bits/s) by the number of symbols (32).

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  • Understanding of baud rate and bit rate concepts
  • Knowledge of analog signaling techniques
  • Familiarity with phase shift keying and amplitude modulation
  • Basic logarithmic calculations
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  • Research the principles of phase shift keying (PSK)
  • Learn about amplitude modulation (AM) techniques
  • Explore baud rate calculations in digital communications
  • Investigate the differences between baud rate and bit rate
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Electrical engineers, telecommunications professionals, and anyone involved in data transmission using analog signaling techniques.

Punkyc7
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We are using analog signaling to transmit our data. If we utilize 4 different phase shifts and 8 different amplitudes and the bit rate is 100 Kbits/s what is the baud rate of the channel?




I was thinking that it is


log_{2} (4 * 8)/100 =1/20




but i think it is wrong.
 
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I'm very rusty so might be totally wrong but...

The baud rate is generally the symbol rate. If I've understood correctly you have 32 different symbols/combinations (4 * 8 = 32). So I believe the baud rate is 100,000/32.
 

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