Calculating Bubble Velocity and Work in a Fluid Container | Help with Pressure

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To calculate the velocity of a bubble rising in a fluid, the buoyant force can be expressed as Fb = ρf * v * g, where ρf is the fluid density and v is the bubble volume. The work done by this buoyant force as the bubble ascends to the surface is given by Work = Fb * H, leading to Work = ρf * v * g * H. By applying the conservation of energy principle, this work equals the kinetic energy of the bubble, allowing for the determination of its velocity. The mass of the bubble can be calculated as ρa * v, where ρa is the air density, facilitating the final calculation of bubble velocity.
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1. A bubble of air of volume v forms at the bottom of a container of fluid (neglect effects of viscosity). Let H be the height of the fluid, and let ρf and ρa denote densities of fluid
and air respectively. How fast is the bubble moving when it reaches the surface?

2. What is the work performed by the buoyant force on the bubble from the moment it
forms on the bottom until it reaches surface?

2. v=vo+at, F=ma, Fb=pvg
3. I have no clue how to solve this. I am assuming it has to do with the equation P(h)= P(O) +pgH and maybe kinematics? For part b i used Fb=pv(of air)g and multiplied it times H so work=pvgH Thanks
 
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Buoyant force = pf*v*g
Work done by the buoyant force = pf*v*g*H. According to the conservation of energy this work done must be equal to the KE of the bubble. Maas of the bubble = pa*v. Now you can find the velocity of the bubble.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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