Calculating Buoyant Force: Ice in Water

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SUMMARY

The buoyant force on 0.70 kg of ice floating in liquid water is determined by the weight of the water displaced, which is equal to the weight of the ice itself, resulting in a buoyant force of approximately 6.86 N upward. When the ice is submerged, the buoyant force remains the same at 6.86 N upward, as it is still based on the volume of water displaced. The density of water is crucial for these calculations, and the density of ice is less than that of water, which allows it to float. Understanding these principles is essential for solving buoyancy problems in fluid mechanics.

PREREQUISITES
  • Understanding of Archimedes' principle
  • Knowledge of density calculations (density = mass/volume)
  • Familiarity with the concept of equilibrium in forces
  • Basic grasp of fluid mechanics
NEXT STEPS
  • Study Archimedes' principle in detail
  • Learn how to calculate buoyant forces for various materials
  • Explore the relationship between density and buoyancy
  • Investigate applications of buoyancy in engineering and design
USEFUL FOR

Students studying physics, particularly those focusing on fluid mechanics, as well as educators and anyone interested in understanding buoyant forces and their applications in real-world scenarios.

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Homework Statement



(a) What is the buoyant force on 0.70 kg of ice floating freely in liquid water?
_____ N upward

(b) What is the buoyant force on 0.70 kg of ice that is held completely submerged under water?
______N upward

Homework Equations



?

The Attempt at a Solution



How do you calculate the buoyant force of an object in another object as it states here?
 
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The buoyant force is equal to the weight of the water displaced. Is that enough to get started?
 
The buoyant force is equal to the weight of the water that is displaced.
If we look at the first problem, we can see that it's in equilibrium, which means all the forces are equal. Should be easy to solve the first one now.

The second one, I think you have to assume that the ice's density is the same as the waters. Because just from the mass, that doesn't help us. A 0.70kg piece of gold will have far less buoyant forces than a 0.70kg piece of ice. Since there's no other information here, we'll have to assume the ice's density.
 
Objects will sink until the buoyant force is equal to the object's weight. The size of the buoyant force is equal to the weight of the displaced water.
 
ok i got the first one, now i am still confused on how to find it if it is held under the water.
 
Density = mass/volume
You should know the density of water.

The density of ice is more, but using the density of water should be alright here. Unless they've given you it's density.
 
Last edited:
so it is the density of water = mass of ice cube/volume of ?? what
 
Volume of the ice cube, if it's density were equal to that of water, which it almost is.
Then refer back to the question with your new information, and you can solve it.
 
i am still not getting the right answer..I put it into the equation (rho)(gravity)(volume)
 
  • #10
got it.. thanks everyone for the help!
 

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