The capacitance of a water-filled parallel-plate capacitor with a plate area of 3.0×10−3 m2 and a separation of 4.0×10−2 mm is calculated using the formula C = Kε0A/d. The correct dielectric constant (K) for water is necessary for accurate calculations. The final capacitance value is determined to be 53 nF, confirming that the initial calculation using ε0 alone was incorrect.
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pat666 said:Homework Statement
The capacitance of a water-filled parallel-plate capacitor with plate area 3.0×10^−3m^2 and separation 4.0×10^−2 mm is
0.66 uF
1.3 nF
53 nF
660 nFHomework Equations
C=E_0A/d
The Attempt at a Solution
C=8.85*10^-12*3*10^-3/4*10^-5
C=6.64*10^-10
This is none of the options. I think that the constant 8.85*10^-12 may be wrong since the capacitor is water not air?