Calculating Centripetal Acceleration and Force on Child

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SUMMARY

The discussion focuses on calculating centripetal acceleration and net horizontal force for a child on a merry-go-round. Using the formula for centripetal acceleration, the child’s acceleration is determined to be 0.29 m/s² with a mass of 25 kg and a radius of 7.8 m. The net horizontal force exerted on the child is calculated using the formula Fc = mv²/r, resulting in a force of 7.21 x 10^4 N. These calculations demonstrate the application of fundamental physics equations in real-world scenarios.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula
  • Knowledge of Newton's second law of motion
  • Familiarity with basic algebra for manipulating equations
  • Concept of mass and force in physics
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Explore real-world applications of centripetal force in amusement park rides
  • Learn about the effects of varying mass and speed on centripetal force
  • Investigate the relationship between radius and centripetal acceleration
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Students studying physics, educators teaching mechanics, and anyone interested in the dynamics of circular motion.

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Homework Statement


A child (mass=25kg) moves with a speed of 1.50ms-1 when 7.8m from the centre of a merry-go-round. Calculate
a) the cetripetal acceleraton of the child
b) th net horizontal force exerted on the child

Homework Equations


centripetal acceleration = v2/r
Fc=mv2/r

The Attempt at a Solution



centripetal acceleration = (150)2(squared)/7.8
=0.29m/s2

do i work out the horizontal force exerted on the child by using Fc=mv2/r?
25*(150)2(squared)/7.8 =7.21*10^4 N
 
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correct. Good job.
 
gee thanks for your time
 

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