Calculating Centripetal Acceleration in a Speed Skater's Turn

[Dylan6866]

Homework Statement

A short track speed skaer is making a turn at one end an ice rink, increasing his speed frm uniformly 10 m/s t 20 m/s in two seconds. The radius of the turn is 5 meters. While he is in the middle of the turn, and mving at 15 m/s, what is

a. tangential acceleration
b. centripetal acceleration
c. magnitude of his acceleration

Homework Equations

v^2/r
magnitude of a = sqrt((tangential)^2+(centripetal)^2)

The Attempt at a Solution

tangential= 15 m/s
centripetal=(15m/s)^2/(5m)=45m/s^2
magnitude of acceleration = sqrt((15)^2+(45)^2)=47.43

Please help me out here.

 

[SammyS]

Homework Statement

A short track speed skaer is making a turn at one end an ice rink, increasing his speed frm uniformly 10 m/s t 20 m/s in two seconds. The radius of the turn is 5 meters. While he is in the middle of the turn, and mving at 15 m/s, what is

a. tangential acceleration
b. centripetal acceleration
c. magnitude of his acceleration

Homework Equations

v^2/r
magnitude of a = sqrt((tangential)^2+(centripetal)^2)

The Attempt at a Solution

tangential= 15 m/s
centripetal=(15m/s)^2/(5m)=45m/s^2
magnitude of acceleration = sqrt((15)^2+(45)^2)=47.43

Please help me out here.

Hello Dylan6866. Welcome to PF.

If you mean that the tangential acceleration = 15m/s, I'm afraid that's wrong. Wrong units and wrong number.

The centripetal acceleration is correct.

 

[Dylan6866]

Hello Dylan6866. Welcome to PF.

If you mean that the tangential acceleration = 15m/s, I'm afraid that's wrong. Wrong units and wrong number.

The centripetal acceleration is correct.

Thank you. I figured it out.