Calculating Charge and Acceleration of Two Charged Spheres

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Homework Help Overview

The problem involves two small charged spheres, each with a mass of 8.55 grams, positioned 20.0 cm apart. The objective is to determine the number of electrons that must be added to each sphere to achieve an acceleration of 15.0 g upon release, while disregarding other forces.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between force, mass, and acceleration, referencing relevant equations. There are attempts to equate forces and solve for charge, with some questioning the significance of the specified acceleration of 15.0 g.

Discussion Status

Some participants have provided calculations and corrections regarding the setup, including clarifications about the distance between the spheres and the interpretation of acceleration. There is an ongoing exploration of the calculations without a clear consensus on the final answer.

Contextual Notes

Participants note the importance of understanding the acceleration as a multiple of gravitational acceleration and clarify the distance between the spheres, which is critical for the calculations. There is acknowledgment of a mistake in the initial setup regarding the distance used in the equations.

Josh930
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Homework Statement



Two very small 8.55-g spheres, 20.0cm apart from center to center, are charged by adding equal numbers of electrons to each of them.

Disregarding all other forces, how many electrons would you have to add to each sphere so that the two spheres will accelerate at 15.0 g when released?

Homework Equations



F=ma
F=k(q1q2/r^2)
q=ne



The Attempt at a Solution



for one.. i don't know why the acceleration is at 15.0 g?

But i did try to set the forces equal and solve q, then plugged q into the equation q=ne and it wasn't right.

Please help
 
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Show your calculations.
 
F=ma=F=k(q1q2/r^2)

q1=q2; let Q^2=q1q2

sqrt(mar^2/k)=Q

sqrt((8.55g*15.0m/s)((2m)^2)/k)=Q

Q=2.39e-4

Q=ne

n=2.39e-4/1.6e-19

=1.49e15 electrons
 
The acceleration is 15*g i.e. 15*9.8 m/s^2
In the solution you have written (2m)^2. What is that?
 
they are 20cm apart? so .2m
 
i messed up and wrote 2m. so 15g is 15x the acceleration of gravity
 
Yes.
 

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