Correct statement about force between two charges

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Homework Help Overview

The discussion revolves around the electrostatic forces between two conducting spheres with given charges and distances. Participants are analyzing the implications of Coulomb's law in the context of the charge distribution on the spheres and the distances involved.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the effects of charge distribution on the forces between the spheres, considering whether the charges are evenly distributed. There is discussion about the implications of different answer choices based on the distance between the centers of charge distribution versus the surfaces of the spheres.

Discussion Status

The conversation is active, with participants questioning the validity of various answer choices. Some suggest that options C and D could be correct, while others argue against B and E based on the reasoning about distances. There is an ongoing exploration of how the amount of charge might influence the outcome.

Contextual Notes

Participants are considering the specific distances involved, including the distance between the centers of charge and the surfaces of the spheres, as well as the potential implications of using different values for charge in their reasoning.

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Homework Statement


Two conducting spheres A and B, of radii ra and rb, carry charges +Qa and - Qb respectively. The centers of the spheres are a distance d apart with d slightly greater than ra+rb. Which of the following statements about the electrostatic forces F between the spheres is true?
a. F < k QaQb/d2
b. F = k QaQb/d2
c. F > k QaQb/d2
d. F < k QaQb/(d - ra - rb)2
e. F > k QaQb/(d - ra - rb)2

Homework Equations


Coulomb's law

The Attempt at a Solution


My answer is B but I am considering another answer which is C because the charge on each sphere is not evenly distributed throughout the surface but will be collected to one side of the sphere. So it is B or C?

Thanks

Edit: revising choices of answer
 
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songoku said:
the charge on each sphere is not evenly distributed throughout the surface but will be collected to one side of the sphere.
Right, but in a way that increases or reduces the attraction?

What about d and e? Could one of those be true too?
 
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haruspex said:
Right, but in a way that increases or reduces the attraction?
The center of charge distribution is not same as center of sphere anymore so the center of the charge distribution is less than d, making the attractive force bigger

What about d and e? Could one of those be true too?
The distance in the denominator is from surface to surface so it may not represents the distance from center of charge to center of charge.

Edit: I just realized that option (d) is possible because the distance between the center of charge distribution is bigger than distance from surface to surface
 
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songoku said:
The center of charge distribution is not same as center of sphere anymore so the center of the charge distribution is less than d, making the attractive force biggerThe distance in the denominator is from surface to surface so it may not represents the distance from center of charge to center of charge.

Edit: I just realized that option (d) is possible because the distance between the center of charge distribution is bigger than distance from surface to surface

What if ##Q_a = -e## and ##Q_b = e##, where ##e## is the charge on an electron?
 
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PeroK said:
What if ##Q_a = -e## and ##Q_b = e##, where ##e## is the charge on an electron?

Does the amount of charge affect the answer?

Thanks
 
songoku said:
Does the amount of charge affect the answer?

Thanks

What do you think? Why did I suggest this example? Do some calculations.
 
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PeroK said:
What do you think? Why did I suggest this example? Do some calculations.

Sorry I do not know what to calculate and I do not understand the purpose of your hint.

Changing the amount of charge will change the magnitude of the force but in my opinion in this question the distance is the variable that I need to consider, not the charge.

I think changing the charge won't affect the distance or maybe not significantly.

Thanks
 
songoku said:
Sorry I do not know what to calculate and I do not understand the purpose of your hint.

Changing the amount of charge will change the magnitude of the force but in my opinion in this question the distance is the variable that I need to consider, not the charge.

I think changing the charge won't affect the distance or maybe not significantly.

Thanks

What do you think about d)? It looks like a good answer to me, at first sight at least. Can you see why answer e) is impossible?
 
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PeroK said:
What do you think about d)? It looks like a good answer to me, at first sight at least. Can you see why answer e) is impossible?

I think there are two correct answer C or D.

B is not possible because the distance needed to calculate the force is not equal to d.

E is not possible because the distance should be bigger than d - ra - rb so the force will be less than that
 
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songoku said:
I think there are two correct answer C or D.

B is not possible because the distance needed to calculate the force is not equal to d.

E is not possible because the distance should be bigger than d - ra - rb so the force will be less than that

That's not a bad answer. Technically, if there is only one unit of charge on each sphere, then those charges would end up precisely ##d - r_a - r_b## apart and you would have equality in equation d). So, technically, d) would need to be ##\le## to be correct in all cases.

I'm not sure whether the question setter intended you to think about this. If there is only one correct answer, then it must be c). It's "more correct" than d). It doesn't say "in all cases" and d) is usually true.
 
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  • #11
I understand.

Thank you very much for the help haruspex and perok
 

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