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Miike012

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The problem and solution are in the document.

My question is in regards to the solution about calculating the charge on the capacitor. Would an equally correct solution for the charge be...

Let σ

The plate is a conductor and I would assume that the thickness throughout the plate is uniform, and there should be no divots or anything that would create the charge density in some area of the plate to be greater than another area of the plate.

Thus σ

Therefore Q = ∫

σ

(ds is obviously a differential surface area of the capacitor)

FINAL: Charge of capacitor (Q) = σ

My question is in regards to the solution about calculating the charge on the capacitor. Would an equally correct solution for the charge be...

Let σ

_{s}be the surface charge density on the plate.The plate is a conductor and I would assume that the thickness throughout the plate is uniform, and there should be no divots or anything that would create the charge density in some area of the plate to be greater than another area of the plate.

Thus σ

_{s}is uniform.Therefore Q = ∫

_{s}σ_{s}ds = σ_{s}[∫_{s}ds] =σ

_{s}[(pi)(a^{2})] where a is the radius of the circular capacitor.(ds is obviously a differential surface area of the capacitor)

FINAL: Charge of capacitor (Q) = σ

_{s}[(pi)(a^{2})]