Calculating Charge & Radius of a Van der Graaff Generator Dome

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SUMMARY

The maximum electrical potential of a Van der Graaff generator dome is 600 kV, with an electric field strength of 3.0 MV/m. To calculate the charge (q) and radius (r) of the dome, the equations E = kq/r² and V = kq/r are utilized. By substituting the known values into these equations, one can derive the necessary parameters for the dome's design. This approach ensures accurate calculations for both charge and radius based on the provided electrical specifications.

PREREQUISITES
  • Understanding of electrostatics, specifically electric potential and electric fields.
  • Familiarity with the equations E = kq/r² and V = kq/r.
  • Knowledge of the constants involved, such as Coulomb's constant (k).
  • Basic algebra skills for manipulating equations to solve for unknowns.
NEXT STEPS
  • Study the derivation and application of Coulomb's law in electrostatics.
  • Learn how to manipulate equations involving electric fields and potentials.
  • Explore practical applications of Van der Graaff generators in physics experiments.
  • Investigate safety measures and considerations when working with high-voltage equipment.
USEFUL FOR

Physics students, electrical engineers, and educators involved in teaching electrostatics and high-voltage systems will benefit from this discussion.

riincanavi1
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1. A spherical dome of a Van der Graaff genenerator can be raised to a maximum electrical
potential of 600 kV; then additional charge leaks off in sparks as the electric field reaches 3.0
MV/m. Determine the charge and radius of the dome.



2. Homework Equations [E=kq/r^2 and V=kq/r]



3. I don't know how to relate the given Voltage and the given E field to find charge and radius
 
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You'll use the equations you quoted, for the values given in the problem statement.

I.e.,

3.0 MV/m = kq/r^2
600 kV = kq/r

Work with those to get r and q.
 

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