Calculating <\chi_3|H|\chi_3> w/ Dirac Notation Algebra

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The discussion centers on calculating the expression <\chi_3|H|\chi_3> using Dirac notation algebra, specifically with the state |\chi_3\rangle=|a+ib\rangle. The initial proposal for the calculation is corrected by noting that bras are antilinear, leading to the adjustment of terms such as <ib|H|a> to -i<b|H|a>. The clarification emphasizes the importance of standard notation, suggesting that |a+ib\rangle should be interpreted as |a\rangle+i|b\rangle for accurate results.

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roro-rose
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Say we have,
|\chi_3>=|a+ib> and we want : <\chi_3|H|\chi_3>

is it correct to say:
<\chi_3|H|\chi_3>= <a|H|a>+<a|H|ib>+<-ib|H|a>+<-ib|H|ib> ??
 
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roro-rose said:
Say we have,
[tex] |\chi_3\rangle=|a+ib\rangle ~~\mbox{and we want:}~~ \langle\chi_3|H|\chi_3\rangle[/tex]

is it correct to say:
[tex] \langle\chi_3|H|\chi_3\rangle ~=~ \langle a|H|a\rangle ~+~ \langle a|H|ib\rangle<br /> ~+~ \langle -ib|H|a\rangle ~+~ \langle -ib|H|ib\rangle ??[/tex]

That's almost right, except that bras are antilinear, hence
[tex] \langle ib| ~=~ -i \langle b|[/tex]

So, e.g, your 3rd term should be
[tex] \langle ib|H|a\rangle ~=~ -i \langle b|H|a\rangle[/tex]

HTH.
 
It really depends on what you mean by [itex]|a+ib\rangle[/itex], which is not a standard notation. Do you mean [itex]|a\rangle+i|b\rangle[/itex]? if so, then strangerep's correction of your result is the right answer.
 

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