Calculating Clay's Acceleration: 12.0 m Fall

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SUMMARY

The discussion centers on calculating the average acceleration of a ball of moist clay that falls 12.0 meters and is in contact with the ground for 22.0 milliseconds. To determine the average acceleration, one must first calculate the final speed of the clay upon impact using the equation v^2 = u^2 + 2gh, where g is the acceleration due to gravity. The average acceleration can then be derived from the change in velocity over the time of contact with the ground.

PREREQUISITES
  • Understanding of kinematic equations, specifically v^2 = u^2 + 2gh
  • Knowledge of the concept of average acceleration
  • Familiarity with basic physics principles regarding free fall
  • Ability to perform calculations involving time and velocity
NEXT STEPS
  • Calculate the final speed of the clay using the kinematic equation
  • Determine the average acceleration using the formula a = (v - u) / t
  • Explore the effects of different heights on average acceleration
  • Review concepts of impulse and momentum in relation to contact time
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Students studying physics, particularly those focusing on kinematics and dynamics, as well as educators looking for examples of real-world applications of acceleration calculations.

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Homework Statement



A ball of moist clay falls 12.0 m to the ground. It is in contact with the ground for 22.0 ms before stopping.
(a) What is the average acceleration of the clay during the time it is in contact with the ground? (Treat the ball as a particle.)

Homework Equations


v^2 = u^2 + 2gh
v=final speed
u= initial speed

The Attempt at a Solution


I'mm not sure where to start this, as I don't think it is asking about the whole thing, but the 22 ms? I'm lost here.
 
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Ok, well first you could figure out how fast the ball is going when it hits the ground.

The next step is to ask yourself what the definition of average acceleration is and see if you have all the information you need to solve for it.
 

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