Calculating Closest Approach Distance for Two Moving Protons

  • Thread starter Thread starter kdrobey
  • Start date Start date
  • Tags Tags
    Approach
Click For Summary

Homework Help Overview

The problem involves two protons moving directly toward one another, with the goal of determining the distance of closest approach based on their initial speeds. The context is rooted in concepts of kinetic and potential energy in a physics framework.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of energy principles, questioning the correct application of kinetic and potential energy equations. There are attempts to clarify the total kinetic energy of both protons and how it relates to potential energy.

Discussion Status

The discussion has seen participants providing hints and guidance regarding the conservation of energy, with some clarifying the need to consider both protons' kinetic energies. There is a progression toward understanding the correct relationship between kinetic and potential energy, although not all participants have reached a resolution.

Contextual Notes

Participants are working under the constraints of a homework assignment, which requires them to show their thought processes and attempts at solving the problem. There is an emphasis on understanding rather than simply providing answers.

kdrobey
Messages
27
Reaction score
0

Homework Statement



Two Protons are moving directly toward one another. When they are very far apart, their initial speeds are 2.1 x 10^6 m/s. What is the distance of closest approach?

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Show what you've done so far.

Hint: What's conserved?
 
Your are expected to show an attempt at the problem. What are your thoughts on the problem?
 
ok, will do
 
Okay I have the same problem except my initial speed is 1.2*10^6

So, I used the equation 1/2mVo^2 = Kq^2/r

I am solving for r and I keep getting 1.92 * 10^-13, but it is wrong. What am I doing wrong?
 
Realize that both protons are moving and thus have kinetic energy.
 
So, I am using the wrong formula? Not getting it...
 
You need to set total KE equal to PE.
 
I thought that is what I did
 
  • #10
What's the KE of each proton? (Symbolically--no need for numbers yet.)
 
  • #11
I am not sure what you are looking for
 
  • #12
nckaytee said:
I am not sure what you are looking for
The basic expression for the KE of each proton, like you used in post #5.
 
  • #13
1/2mVo^2
 
  • #14
nckaytee said:
1/2mVo^2
Good. That's the KE of one proton. So what's the total KE of both protons?
 
  • #15
so,

1/2mVo^2 + 1/2mVo^2= Kq^2/r

?
 
  • #16
Good.
 
  • #17
Okay I got the correct answer 9.6e-14 ... finally :-)
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
1
Views
2K
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
Replies
5
Views
3K