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**[SOLVED] Calculating coefficient of kinetic friction**

## Homework Statement

An applied force of 450 N {forward} is needed to drag a 1000-kg crate at constant speed across a horizontal, rough floor. Calculate the coefficient of kinetic friction for the crate on the floor.

Fapp=450 N {forward}

m=1000 kg

a=0

g=9.81 m/s^2

## Homework Equations

Fnet=F(f(kinetic)) + F(app) + F(g)

Fnet=ma

Ffkinetic=-(mu)kFn

Fg=-mg

## The Attempt at a Solution

Fnet=-(mu)kFn + Fapp + Fg

Since Fnet = ma

ma=-(mu)kFn + Fapp + Fg

0=-(mu)k1000 + 450 - 1000(9.81)

(mu)k1000=-9360

(mu)k=-9.36

The answer is supposed to be 4.59 x 10^-2, which makes a whole lot more sense than -9.36. I'm completely lost. The text only has one example and it's completely different from this question. tia!