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- Homework Statement
- A 30kg object is being pulled across a horizontal surface. The acceleration is 1.2 m/s2. The object is being pulled by a handle that is at 25 degrees. Friction force is 10 N. What forces can we find?

- Relevant Equations
- Fg = m * g

Fnet = m * a

Fa = Fax / cos(angle)

Fax = Fax leftward - Fax rightward

Fay = Fa * sin(angle)

Fg = m * g:

Fg = 30 * 9.8 = 294 N

Fnet = m * a:

Fnet = 30 * 1.2 = 36 N

Fax = Fnet + Ff:

Fax = 36 + 10 = 46

Fa = Fax / cos(angle):

Fa = 46 / cos(25) = 50.75

Fay = Fa * sin(angle):

Fay = 50.76 * sin(25) = 21.45

Fn = Fg - Fay:

Fn = 294 - 21.45 = 272.55

Ff = mu kinetic * Fn, solving for coefficient:

Coefficient of friction = 10 / 272.55 = .035Does this look correct?

Fg = 30 * 9.8 = 294 N

Fnet = m * a:

Fnet = 30 * 1.2 = 36 N

Fax = Fnet + Ff:

Fax = 36 + 10 = 46

Fa = Fax / cos(angle):

Fa = 46 / cos(25) = 50.75

Fay = Fa * sin(angle):

Fay = 50.76 * sin(25) = 21.45

Fn = Fg - Fay:

Fn = 294 - 21.45 = 272.55

Ff = mu kinetic * Fn, solving for coefficient:

Coefficient of friction = 10 / 272.55 = .035Does this look correct?