Calculating Constant Acceleration for a Cessna Aircraft Takeoff

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
8 replies · 4K views
nbroyle1
Messages
43
Reaction score
0
A Cessna aircraft has a liftoff speed of 120 km/h.

(a) What minimum constant acceleration does the aircraft require if it is to be airborne after a takeoff run of 250 m?
(b) How long does it take the aircraft to become airborne?

I tried using an equation for constant acceleration and plugged in: .277^2=0+2a(250). When I solved for a I got .000153 and it was incorrect. any suggestions?
 
Physics news on Phys.org
nbroyle1 said:
A Cessna aircraft has a liftoff speed of 120 km/h.

(a) What minimum constant acceleration does the aircraft require if it is to be airborne after a takeoff run of 250 m?
(b) How long does it take the aircraft to become airborne?

I tried using an equation for constant acceleration and plugged in: .277^2=0+2a(250). When I solved for a I got .000153 and it was incorrect. any suggestions?
Where did the "0.277" figure come from?

(Edit: And does 27.7 centimeters per second even sound like a reasonable velocity for the liftoff speed of a Cessna aircraft?)
 
After I converted the kilometers per hour to meters per second
 
nbroyle1 said:
After I converted the kilometers per hour to meters per second
You might want to try that calculation again. :smile:
 
thats my problem it should be 44.44m/s
 
nbroyle1 said:
thats my problem it should be 44.44m/s
Ummm, :rolleyes: Try that one more time. :smile:
 
i meant 33.33m/s haha
 
nbroyle1 said:
i meant 33.33m/s haha
That sounds better. :approve: