How Do You Calculate Minimum Constant Acceleration for a Jumbo Jet Takeoff?

[Physicsnoob90]

I'm confuse by what the question is asking as far as the conversion (km/hr/s). Can any please help me?

Homework Statement

A jumbo jet must reach a speed of 240 km/hr on the runway for takeoff. What is the minimum constant acceleration (in km/hr/s) needed for takeoff from a 1.34 km runway? (3 sig fig)

Homework Equations

The Attempt at a Solution

a=vf^2/2(Δx)

a=(240 km/hr)^2/2(1.34 km) = (57600 km^2/hr^2) / (2.68 km) = 21492.53731

 

[Physicsnoob90]

Ignore this question. Finally solved it!

 

[NihalSh]

I'm confuse by what the question is asking as far as the conversion (km/hr/s). Can any please help me?

Homework Statement

A jumbo jet must reach a speed of 240 km/hr on the runway for takeoff. What is the minimum constant acceleration (in km/hr/s) needed for takeoff from a 1.34 km runway? (3 sig fig)

Homework Equations

The Attempt at a Solution

a=vf^2/2(Δx)

a=(240 km/hr)^2/2(1.34 km) = (57600 km^2/hr^2) / (2.68 km) = 21492.53731

Your answer is correct, in $km/hr^2$!...you want to convert units?...

$$21492.53731\frac{km}{hr^2}=21492.53731\frac{km}{hr^2}*\frac{1 hr}{60 min}*\frac{1 min}{60 sec}=? \frac{km}{hr.sec}$$

Remember only three significant figures.

Edit : I guess you solved it!