Calculating Critical Density Using FRW and Its Implications

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SUMMARY

The discussion centers on calculating critical density using the Friedmann-Robertson-Walker (FRW) metric, specifically through the equation (\dot{a}/a)^2 = (8 \pi G \rho)/3 - (k c^2)/a^2. Critical density is defined as \rho_c = (3 H^2)/(8 \pi G), where H is the Hubble parameter. It is established that the density \rho includes contributions from the cosmological constant \Lambda, and the universe's fate is determined by its density relative to critical density: \rho_c leads to a halt in expansion, \rho > \rho_c results in collapse, and \rho < \rho_c allows for perpetual expansion. Measurements of the universe's density suggest it is slightly less than critical, aligning with the notion of a flat universe.

PREREQUISITES
  • Understanding of Friedmann-Robertson-Walker (FRW) metric
  • Familiarity with Hubble parameter and critical density calculations
  • Knowledge of cosmological constant and its implications
  • Basic principles of cosmology and universe expansion
NEXT STEPS
  • Research methods for measuring cosmic density, including supernova and CMB data fitting
  • Study the implications of dark energy on cosmic expansion
  • Explore the relationship between density parameters \Omega_M, \Omega_R, and \Omega_{\Lambda}
  • Investigate the concept of flatness in cosmology and its observational evidence
USEFUL FOR

Astronomers, cosmologists, and physics students interested in the dynamics of the universe, critical density calculations, and the role of dark energy in cosmic expansion.

CaptainMarvel
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Using the FRW:

[tex] \left( \frac {\dot{a}} {a} \right)^2 = \frac {8 \pi G \rho} {3} - \frac {k c^2} {a^2}[/tex]

We define critical density by setting k = 0 and rearranging to get:

[tex] \rho_c = \frac {3 H^2} {8 \pi G}[/tex]

Where:

[tex] H = \left( \frac {\dot{a}} {a} \right)[/tex]

My question is does [tex]\rho[/tex] include the density contribution for Cosmological Constant (dark energy) [tex]\Lambda[/tex] or is this derivation only for a Universe with no cosmological constant?

How does one then actually measure the density of Universe?

I know that the density has been measured to be slightly less than the critical density, but I thought we are meant to live in a flat Universe? Is this due to the cosmological constant and how is this reconciled with [tex]\rho[/tex] not being exactly [tex]\rho_c[/tex]?

Finally, I am right in saying that a Universe with [tex]\rho_c[/tex] will stop expanding after infinite time, one with [tex]\rho > \rho_c[/tex] will collapse back on itself and one with [tex]\rho < \rho_c[/tex] will expand forever?

Many thanks.
 
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Yes, [itex]\rho[/itex] includes contribution from the cosmological constant. In other words, we can write the density as a function of scale factor as
[tex] \rho = \rho_c\left(\Omega_Ma^{-3} + \Omega_Ra^{-4} + \Omega_{\Lambda}\right)[/tex]

Finally, I am right in saying that a Universe with [tex]\rho_c[/tex] will stop expanding after infinite time, one with [tex]\rho > \rho_c[/tex] will collapse back on itself and one with [tex]\rho < \rho_c[/tex] will expand forever?
This is basically correct, although I don't think, "stop expanding after infinite time" is a well-defined notion.

How does one then actually measure the density of Universe?
Fit supernova data and/or CMB data to different models and see what works best.

I know that the density has been measured to be slightly less than the critical density, but I thought we are meant to live in a flat Universe? Is this due to the cosmological constant and how is this reconciled with [tex]\rho[/tex] not being exactly [tex]\rho_c[/tex]?
The measurement of [tex]\rho[/tex] is within error of being less than, equal to, or greater than the critical density. People say we live in a "flat universe", because the measured value is very close to the critical density.
 
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