Calculating Current in a Transformer with Known Parameters and Load Impedance

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SUMMARY

The discussion focuses on calculating the primary and secondary currents (I1 and I2) in a transformer with specified parameters: R1=0.286 ohm, R2=0.319 ohm, Rc=240 ohm, X1=0.73 ohm, X2=0.73 ohm, and Xm=49.2 ohm. The secondary load impedance is given as ZL=0.387+J0.29. The correct formula for calculating the primary current I1 is I1 = V1 / (Z1 + Zm // (Z2' + ZL')), which simplifies to I1 = V1 / (Z1 + Zm * (Z2' + ZL') / (Zm + Z2' + ZL')). This formula is confirmed as accurate for determining the current in the transformer circuit.

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Homework Statement



The prameters of 2300/230 v 50hz t/f is
R1=0.286 ohm R`2=0.319 ohm Rc=240 ohm
X1=0.73 ohm X`2=0.73 ohm Xm=49.2 ohm

Secondary Load impedance ZL=0.387+J0.29

solve the exact equivalent circuit with normal voltage across primery..

I know every thing but i can't find CURRENT I1=? and I`2=?



Homework Equations



I know every thing but i can't find CURRENT I1=? and I`2=?

The Attempt at a Solution



only Formula please
 
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I1 = V1 / (Z1 + Zm//(Z2' + ZL')), which becomes
I1 = V1 / (Z1 + Zm * (Z2' + ZL') / (Zm + Z2' + ZL'))

this is right??
 

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