1. The problem statement, all variables and given/known data Calculate the density of Iron with the following information. side length = 2.86 angstroms Atomic weight = 55.85 Body centered cubic, so 2 atoms per unit cell. 2. Relevant equations Density = ((# of atoms)(Atomic Weight)) / ((volume of cell)/Avogadro's Number)) 3. The attempt at a solution So this should be really easy, but I can't get the correct number with this formula, what am I doing wrong? Atomic Weight of 55.85 means a mass of 9.274117017e-26 kg. Side Length of 2.87 angstroms mean that the side length is 2.87E-10 Meters. Cube this side length to get the total volume. so using the formula... (2)(9.274117E-26) / (2.87E-10)^3*(6.022^23) = 1.302915E-20 kg/m^3.. which is obviously very incorrect... Help meh?