Calculating Density Using Archimedes Principle

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SUMMARY

The discussion centers on calculating the density of a block of wood using Archimedes' Principle. The block, measuring 40 cm in length and 15 cm2 in cross-section, floats with 3/8 of its length above water. The correct density of the wood is determined to be 0.625 g/cm3, which is 5/8 that of water, as the upward thrust equals the weight of the water displaced. Participants clarified the importance of using consistent units and the relationship between buoyancy and weight in floating objects.

PREREQUISITES
  • Understanding of Archimedes' Principle
  • Basic knowledge of density calculations
  • Familiarity with units of force (Newtons) and mass (grams)
  • Concept of buoyancy and equilibrium in floating objects
NEXT STEPS
  • Study the derivation of Archimedes' Principle in fluid mechanics
  • Learn about the relationship between buoyancy and density
  • Explore unit conversions between grams, Newtons, and other relevant units
  • Investigate real-world applications of buoyancy in engineering and design
USEFUL FOR

Students studying physics, educators teaching fluid mechanics, and anyone interested in understanding the principles of buoyancy and density calculations.

physics kiddy
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I have found a question that has got to my nerves :

A block of wood of length 40 cm and area of cross-section 15 cm2 floats in water with 3/8 of it's length above water. What is the density of wood ? (Density of water - 1g/cm3).

My attempt to get the solution :

Length of wood above water = 3/8 * 40 = 15cm
Length of wood below water = (40-15)cm = 25cm

Now, Upthrust = 375cm3*1*10 = 3750 N

Rest, I don't know !

Please help. It's urgent because I am going to face some deadly questions the day after tomorrow. Thank You.
 
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When an object floats and is motionless, its weight exactly equals the upward thrust. The upward thrust is the weight of water displaced.

If you know the weight and volume, you can determine the density.

You have an error with your units. The upward thrust is not 3750 Newtons.
 
Then what is it ?
 
You are multiplying cm^3 by grams/cm^3. You do not get Newtons. You get grams. A gram is not a unit of force. Newtons, however, are.

I don't know the purpose of the 10.
 
Last edited:
kg/m^3 times m^3 times gravitational acceleration(m/sec^2) = Newtons

g=9.8 m/sec^2
 
alright , first u need to realize that the upthrust force = the wieght of the body...

ie a floating object displaces it's own wieght of the fluid in which it is floating.

so, F1 = upthrust = 0.0375 * 1000 * 10 = 375
and F2 = weight of block = P*V*g =p*0.06*10

so solving this ... my answer comes out to be 0.625g/cm^-3
 
The upward force is equal to the weight of the water displaced by the body, not the displaced body.
 
physicsvalk said:
The upward force is equal to the weight of the water displaced by the body, not the displaced body.

yes sir, u are right , but in this case aas the object is floating thus there has to be no net force (or otherwise it wud produce an acceleration)

so, keeping Newton's 2 nd law in mind, we can come to the conclusion that :

upthrust = weight of the water displaced by the block of wood
and as there is no acceleration hence
upthrust = actuall weight of the block

Please correct me if i am wrong :)
 
I was correcting your language, not the physics. Yes there is an upward force, but it is not a net force. I never said the upward force was the net force.
 
  • #10
.625 gm/cm^3 is the correct result. It's density is 5/8 that of water because 3/8 of its volume remains above the surface of the water.
 
Last edited:
  • #11
I had a typo in my previous message. Originally I had typed .675 but meant to type .625 gm/cm^3. It has been corrected.
 
  • #12
Oh my god ! I have found the answer. Thanks everybody, thanks.
 

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