Calculating Diffraction Grating Spacing for Red Light | Homework Help

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SUMMARY

The discussion focuses on calculating the spacing of lines in a diffraction grating using the formula for maxima: sin θm = mλ/d. A specific case is presented where a third-order maximum occurs at an angle of 22 degrees for red light with a wavelength of 694.3 nm. The calculated spacing, d, was found to be 5560 nm, which contradicts the textbook answer of 7400 nm, indicating a potential misunderstanding of the order of maximum. Additionally, the discussion addresses calculating the highest spectral order visible for a 6200-line/cm grating with 633-nm laser light.

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  • Understanding of diffraction grating principles
  • Familiarity with the formula for maxima in diffraction: sin θm = mλ/d
  • Basic knowledge of wavelength and its units (nm)
  • Ability to perform trigonometric calculations
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  • Learn how to calculate diffraction grating spacing using different wavelengths
  • Investigate the relationship between angle, wavelength, and order in diffraction patterns
  • Explore the constraints on θ for maximum orders in diffraction gratings
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Hannahj1
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Homework Statement



A diffraction grating produces a third-order maximum, at an angle of 22 degrees, for red light (694.3 nm). Determine the spacing of the lines.

Homework Equations



for maxima:

sin θm = mλ/d

where m is the order of the maxima, λ is the wavelength in nm, and d is the spacing of the lines

The Attempt at a Solution



λ = 694.3 nm
θ = 22
m = 3

d = mλ / sin θ
d = 3 (694.3) / sin 22
d = 5560 nm

but the answer in the textbook is 7400 nm. what have i done wrong?

and this one:

Calculate the highest spectral order visible when a 6200-line/cm grating is illuminated with 633-nm laser light.

d = 1/6200 cm
λ = 633 nm = 6.33 x 10^9 cm
n = ?

how do i find n without θ? I'm probably missing some obvious things
 
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Hannahj1 said:

Homework Statement



A diffraction grating produces a third-order maximum, at an angle of 22 degrees, for red light (694.3 nm). Determine the spacing of the lines.

Homework Equations



for maxima:

sin θm = mλ/d

where m is the order of the maxima, λ is the wavelength in nm, and d is the spacing of the lines

The Attempt at a Solution



λ = 694.3 nm
θ = 22
m = 3

d = mλ / sin θ
d = 3 (694.3) / sin 22
d = 5560 nm

but the answer in the textbook is 7400 nm. what have i done wrong?

and this one:

Calculate the highest spectral order visible when a 6200-line/cm grating is illuminated with 633-nm laser light.

d = 1/6200 cm
λ = 633 nm = 6.33 x 10^9 cm
n = ?

how do i find n without θ? I'm probably missing some obvious things
Are you sure they didn't mean 4th-order maximum?

I'll look at the second question in a few.
 
Student100 said:
Are you sure they didn't mean 4th-order maximum?

I'll look at the second question in a few.

You're setting up an inequality for the second problem, what are the constraints on theta?
 

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