How Does a Diffraction Grating Resolve Different Wavelengths of Sodium Light?

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Homework Help Overview

The discussion revolves around the resolution of different wavelengths of sodium light using a diffraction grating. The specific wavelengths involved are λ_1 = 589.0 nm and λ_2 = 589.89 nm, and the problem involves a grating with 7500 lines/cm.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the maximum order of diffraction, the necessary width of the grating for resolution, and the resolving power. There are questions about the choice of angle θ in the diffraction equation and the implications of dividing wavelength by the difference in wavelengths.

Discussion Status

Participants are exploring various aspects of the problem, including the theoretical maximum angle for diffraction and the implications of the number of lines per centimeter on grating separation. There is an ongoing dialogue about the calculations and the need for integer values for the order of diffraction.

Contextual Notes

Some participants note the absence of specific values for θ and grating separation, which are crucial for further calculations. The discussion reflects uncertainty about how to proceed with the given information.

Eagertolearnphysics
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Homework Statement



Yellow sodium light, which consists of two wavelengths, λ_1 =589.0 nm and λ_2 = 589.89 nm, falls on a 7500 lines/cm diffraction grating. Determine (a) the maximum order m that will be present for sodium light, (b) the width of grating necessary to resolve the sodium lines, (c) the grating resolving power in this case, (d) the angular width of each sodium line.

Homework Equations

The Attempt at a Solution


(a) I divided λ by Δλ and I found it to be 1000, therefore Nm, where m is the order, will be always larger than λ/ Δλ. therefore i don't get how the problem asks for maximum, however, m = 1 is an answer!
(b) I tried mλ = d sinθ but i don't know what θ to use !
(c) it depends on (b)
 
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Eagertolearnphysics said:
(a) I divided λ by Δλ and I found it to be 1000, therefore Nm, where m is the order, will be always larger than λ/ Δλ. therefore i don't get how the problem asks for maximum, however, m = 1 is an answer!

Perhaps you can explain why you divided λ by Δλ ?

The equation I remember is:
mλ = e * sinθ
where m is the order (1,2,3...)
e is the grating separation
θ is the defraction angle for each m
so
m = e/λ * sinθ

What value of θ gives you maximum m?
 
CWatters said:
Perhaps you can explain why you divided λ by Δλ ?

The equation I remember is:
mλ = e * sinθ
where m is the order (1,2,3...)
e is the grating separation
θ is the defraction angle for each m
so
m = e/λ * sinθ

What value of θ gives you maximum m?
the problem doesn't include the value of θ
 
Eagertolearnphysics said:
the problem doesn't include the value of θ
What is the maximum angle you can achieve theoretically?
 
Biker said:
What is the maximum angle you can achieve theoretically?
π/2
 
Correct.

So plug that into the equation and calculate m.
 
CWatters said:
Correct.

So plug that into the equation and calculate m.
But I don't have the grating separation
 
You have the number of lines in 1cm.
Can't you use that to find it?
 
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Yes I can, m = 2.26 but I don't know what to do next !
 
Last edited:
  • #10
Biker said:
You have the number of lines in 1cm.
Can't you use that to find it?
what is the formula for finding angular dispersion of grating? is it the same as angular width?
 
  • #11
Eagertolearnphysics said:
Yes I can, m = 2.26 but I don't know what to do next !

You remember that m must be an integer ..
 

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