Calculating Displacement & Intensity of 1665 Hz Wave

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SUMMARY

The discussion focuses on calculating the displacement amplitude and intensity of a sound wave with a frequency of 1665 Hz and a pressure amplitude of 1.13 x 10^-3 Pa. The displacement amplitude was determined to be 5.25 x 10^-7 m using the formula sm = delta(pm)/(vpw), where pm is the pressure amplitude, p is the density, v is the velocity, and w is the angular frequency. The intensity of the wave emitted by the ear was calculated to be 1.34 x 10^-10 W/m².

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  • Understanding of sound wave properties, including frequency and pressure amplitude
  • Familiarity with the formula for displacement amplitude (sm = delta(pm)/(vpw))
  • Knowledge of angular frequency calculation (w = 2πf)
  • Basic principles of wave intensity calculation
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JasonV
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A sound wave has a frequency of 1665 Hz and a pressure amplitude of 1.13 x 10^-3 Pa. What were (a) the displacement amplitude and (b) the intensity of the wave emitted by the ear?

the equation i used for a is sm=delta(pm)/(vpw)

where p is the density, sm is the displacement amplitude, pm is the pressure amplitude, v is the velocity, and w is the angular frequency.

I could find all of the variables from the equation but the velocity (pm=1.13 x 10^-3, p=1.21, w=2pif=2pi x 1665)
Thanks in advance.
 
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a) The displacement amplitude is 5.25 x 10^-7 m.b) The intensity of the wave emitted by the ear is 1.34 x 10^-10 W/m2.
 

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