Calculating Distance Given Work and Forces

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Homework Statement



A farmhand does 972 J of work pulling an empty hay wagon along level ground with a force of 310 N [23 degrees below the horizontal]. A frictional force of 280 N opposes the motion. The distance the wagon travels is
a. 0.39 m
b. 1.7 m
c. 3.4 m
d. 32 m
e. 1.8 x 102 m

Homework Equations



W=FcosΘd
Fnet=F1+F2

The Attempt at a Solution



W=Fd
d=W/F
d=972/(310cos23-280)
d=180 m

Apparently, the correct answer is c) 3.4 m, which works if you don't account friction, but I don't understand how that's correct.
 
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Natko said:

Homework Statement



A farmhand does 972 J of work pulling an empty hay wagon along level ground with a force of 310 N [23 degrees below the horizontal]. A frictional force of 280 N opposes the motion. The distance the wagon travels is
a. 0.39 m
b. 1.7 m
c. 3.4 m
d. 32 m
e. 1.8 x 102 m

Homework Equations



W=FcosΘd
Fnet=F1+F2

The Attempt at a Solution



W=Fd
d=W/F
d=972/(310cos23-280)
d=180 m

Apparently, the correct answer is c) 3.4 m, which works if you don't account friction, but I don't understand how that's correct.

You have divided the work done by the farmhand by the net force . If you are going to use the net force, you need to use the net work, not the work done by the farmhand.
 
I was wrong
 
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