1. The problem statement, all variables and given/known data A rock is dropped from x(meters) height. The rock weighs 68 kg, and its force at impact with the ground is 15 kilonewtons. If the acceleration due to gravity is 9.8m/s^2, what is the distance/height the rock has fallen? 2. Relevant equations F=m*a 15kN=15000kg*m/s^2 666.4N=68kg*9.8m/s^2 The force exerted by the rock at stationary position is 666.4 Newtons. The rock fall distance is x meters. 3. The attempt at a solution 666.4N*x=15000N (666.4kg*m/s^2)*x=15000kg*m/s^2 x=(15000kg*m/s^2)/(666.4kg*m/s^2) x=22.51 This was all I could come with, but it is simply the ratio of the force. How do I find distance?