 #1
dabbih123
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 Homework Statement:

I have a mass m(A)=2kg on an incline upwards of 30° connected to a pulley system to another mass m(B)=?. The coefficient of friction is 0.18 and the system has an acceleration of 0.58 m/s^2 in the direction up the slope.
What is mass B?
 Relevant Equations:

F=ma
Mass of A = 2 kg
Acceleration = 0.58 m/s^2
μ=0.18
Friction force = μm(A)g cos 30
Component of gravity parallel to ramp = m(A)g sin 30
Force pulled down by m(B)= m(B)g
First I calculated the forces that were working against mass B.
m(A)g sin 30 + μm(A)g cos 30 = 12.86 N
The force working with mass B is
m(B)g = 9.8m(B)
I thought I could solve for B using F=ma where 12.86 N = (2kg+m(B))*(0.58), but of course, 12.86 N is just the force required to make the system move not the force at acceleration 0.58 m/s^2.
I am not sure how to continue or even if I am on the right track.
m(A)g sin 30 + μm(A)g cos 30 = 12.86 N
The force working with mass B is
m(B)g = 9.8m(B)
I thought I could solve for B using F=ma where 12.86 N = (2kg+m(B))*(0.58), but of course, 12.86 N is just the force required to make the system move not the force at acceleration 0.58 m/s^2.
I am not sure how to continue or even if I am on the right track.