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- Homework Statement
- I have a mass m(A)=2kg on an incline upwards of 30° connected to a pulley system to another mass m(B)=?. The coefficient of friction is 0.18 and the system has an acceleration of 0.58 m/s^2 in the direction up the slope.

What is mass B?

- Relevant Equations
- F=ma

Mass of A = 2 kg

Acceleration = 0.58 m/s^2

μ=0.18

Friction force = μm(A)g cos 30

Component of gravity parallel to ramp = m(A)g sin 30

Force pulled down by m(B)= m(B)g

First I calculated the forces that were working against mass B.

m(A)g sin 30 + μm(A)g cos 30 = 12.86 N

The force working with mass B is

m(B)g = 9.8m(B)

I thought I could solve for B using F=ma where 12.86 N = (2kg+m(B))*(0.58), but of course, 12.86 N is just the force required to make the system move not the force at acceleration 0.58 m/s^2.

I am not sure how to continue or even if I am on the right track.

m(A)g sin 30 + μm(A)g cos 30 = 12.86 N

The force working with mass B is

m(B)g = 9.8m(B)

I thought I could solve for B using F=ma where 12.86 N = (2kg+m(B))*(0.58), but of course, 12.86 N is just the force required to make the system move not the force at acceleration 0.58 m/s^2.

I am not sure how to continue or even if I am on the right track.