Calculating Doppler Shift with Ship Sonar and Moving Targets

Click For Summary
SUMMARY

The discussion focuses on calculating the Doppler shift experienced by a whale moving towards a ship's sonar system operating at a frequency of 23.0 kHz, with sound traveling at 1482 m/s in water. The participant initially calculated the frequency of the directly radiated waves as 23,012.4 Hz and the frequency heard by the whale as 23,077 Hz. However, the participant miscalculated the frequency reflected back to the ship, resulting in an incorrect difference of 12 Hz. The error stemmed from using the wrong medium for wavelength calculations.

PREREQUISITES
  • Understanding of the Doppler effect in sound waves
  • Familiarity with sonar systems and their operational frequencies
  • Knowledge of wave properties, including wavelength and frequency
  • Basic proficiency in physics equations related to sound propagation
NEXT STEPS
  • Review the Doppler effect equations, specifically fL = fS(v + vL) / (v + vS)
  • Study the impact of medium changes on sound wave properties
  • Explore practical applications of sonar technology in marine biology
  • Investigate advanced Doppler shift calculations for varying velocities
USEFUL FOR

Students studying physics, marine biologists utilizing sonar technology, and professionals involved in acoustics and sound wave analysis.

jackleyt
Messages
20
Reaction score
0

Homework Statement



The sound source of a ship's sonar system operates at a frequency of 23.0 kHz. The speed of sound in water is 1482 m/s.

What is the difference in frequency between the directly radiated waves and the waves reflected from a whale traveling straight toward the ship at 5.00 m/s? The ship is at rest in the water.

Homework Equations


fL= fS(v+vL)/(v+vS)


The Attempt at a Solution



I got the first part of the question, which was to find the wavelength. The wavelength is 6.44*10^(-2) m. For the second part, I calculated the frequency of the directly radiated waves and got 23,012.4 Hz. Then, I used the Doppler effect equation and got the frequency that the whale heard, which was 23077 Hz. I used that frequency to determine the reflection, and I got 23,000 Hz. The difference was 12 Hz, which was wrong. Can someone help me with what I'm doing wrong? Thanks!
 
Physics news on Phys.org
A couple of things could have gone wrong here, but from what I see they aren't math related. Either:

1) The frequency of the waves reflected from the whale (the waves that the whale is producing) is 23077 Hz. 23 kHz is the frequency of the waves reflected from the whale and heard by the submarine. Small difference but a difference nonetheless.

2) The wavelength you calculated in a) was in a different medium than water.
 
Thanks! It was the latter of the two.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
911
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K