Calculating ECell of Anode-Half Cell? Chemistry Review

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SUMMARY

The discussion centers on calculating the standard electrode potential (E°) of the anode half-cell in the redox reaction involving peroxydisulfate and iodide. Given that E°cell is 1.587 V and E° of the cathode half-cell is 0.536 V, the formula E°cell = E°cathode - E°anode is applied to find E°anode. The solution reveals that E°anode equals 1.051 V, indicating the oxidation potential of the iodide ion in this reaction.

PREREQUISITES
  • Understanding of redox reactions and half-cell potentials
  • Familiarity with the Nernst equation and standard electrode potentials
  • Knowledge of oxidation and reduction processes in electrochemistry
  • Ability to interpret and manipulate electrochemical equations
NEXT STEPS
  • Study the Nernst equation for calculating cell potentials under non-standard conditions
  • Explore the iodine clock reaction and its applications in kinetics
  • Learn about the significance of standard reduction potentials in electrochemistry
  • Investigate the role of oxidation states in redox reactions
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Chemistry students, educators, and anyone interested in understanding electrochemical reactions and their applications in kinetics and redox processes.

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Homework Statement


The redox reaction of peroxydisulfate with iodide has been used for many years as part of the iodine clock reaction which introduces students to kinetics. If E°cell = 1.587 V and E° of the cathode half-cell is 0.536 V, what is E° of the anode half-cell?

S2O82–(aq) + 2H+ + 2I–(aq) → 2HSO4–(aq) + I2(aq)



Homework Equations


I think ECEll= ECathode-EAnode

but not sure



The Attempt at a Solution



have no idea
 
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Voltage is calculated in reduction potentials. Which entity is being reduced and which is being oxidized? If the reduction potential of one entity is a positive number, what is the sign of the contribution to voltage if the entity is being oxidized?
 

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