Calculating Elastic Length in Vertical Circular Motion

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Homework Help Overview

The problem involves a piece of elastic that stretches under a weight and is then used in vertical circular motion. The objective is to determine the length of the elastic at the top and bottom of the circular path after a specified time.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between centripetal acceleration and gravitational acceleration, questioning whether they are equal in this context. There is also mention of applying Newton's second law to analyze the forces involved.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some have provided guidance regarding the forces acting on the elastic in motion, while others are clarifying their understanding of the concepts involved.

Contextual Notes

There is confusion regarding the radius of the circular motion and the initial conditions of the elastic's stretch under the weight. Participants are encouraged to clarify their attempts and reasoning further.

Nightrider00
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Homework Statement



a piece of 4cm elastic stretches to 6.5cm when 100g mass is added. the same piece of elastic is now swung with constant angular velocity in the vertical circular direction.
find the length at the top and bottom of the circular motion when Time=0.2s


Homework Equations





The Attempt at a Solution

 
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Welcome to PF!

Hi Nightrider00! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
I am just confused whether the centripetal acceleration will be equal to the gravitational acceleration or not?
 

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Last edited:
(just got up :zzz: …)
Nightrider00 said:
I am just confused whether the centripetal acceleration will be equal to the gravitational acceleration or not?

no …

almost everything in mechanics comes down to good ol' Newton's second law (F = ma) …

here, there are two forces (gravity and tension), and both must be put into the F = ma equation :smile:
 
So this is what i did... Is this okay
 

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(this is very difficult to read … can't you type it? :redface:)

no, the radius is not 6.5 cm
 
oh okay.. i get it nw.. thanks a lot for the help..:-)
 

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