Calculating Electric Field for a Point Charge Inside a Hollow Sphere

Click For Summary
SUMMARY

The discussion focuses on calculating the electric field for a point charge, q, located at the center of an insulating hollow sphere with inner radius, a, and outer radius, b, using Gauss' Law. The correct electric field for the region where a < r < b is derived from the enclosed charge, which includes both the point charge and the charge distributed in the hollow sphere. The electric field in this region is given by E = (q + (rho * (4/3) * π * r^3)) / (epsilon_0 * (4πr^2)), where rho is the charge density. The initial assumptions regarding the electric field being zero or incorrectly calculated were clarified through further discussion.

PREREQUISITES
  • Understanding of Gauss' Law and its application in electrostatics.
  • Familiarity with electric field concepts and point charge behavior.
  • Knowledge of charge density and its implications in electric field calculations.
  • Basic calculus for integrating charge distributions within spherical coordinates.
NEXT STEPS
  • Study the derivation of electric fields using Gauss' Law in various geometries.
  • Learn about the implications of charge density (rho) on electric fields in conductive and insulating materials.
  • Explore the concept of superposition in electric fields for multiple charges.
  • Investigate the behavior of electric fields in spherical coordinates and their applications in physics problems.
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone seeking to deepen their understanding of electric fields in electrostatic scenarios.

isabellef
Messages
10
Reaction score
0

Homework Statement



A point charge, q, is at the center of an insulating hollow sphere with inside radius, a, and outside radius, b. The spherical shell has charge per unit volume, rho. You may assume that q and rho are positive.

Using Gauss' law, find the magnitude of the electric field for a < r < b.

Homework Equations



Gauss' Law ----> E * dA = Q_encl/epsilon_0

The Attempt at a Solution



I know that the electric field for r < a is E = (rho*r)/(3*epsilon_0).

And the electric field for r > b is E = (rho*b^3)/(3*epsilon_0*r^2).

But I can't seem to figure out the electric field for a < r < b. I've tried using the same method, but I get really confused. I'm thinking that it might just be zero, but I'm not sure.

Any suggestions would be greatly appreciated!
 
Physics news on Phys.org
isabellef said:

Homework Statement



A point charge, q, is at the center of an insulating hollow sphere with inside radius, a, and outside radius, b. The spherical shell has charge per unit volume, rho. You may assume that q and rho are positive.

Using Gauss' law, find the magnitude of the electric field for a < r < b.

Homework Equations



Gauss' Law ----> E * dA = Q_encl/epsilon_0

The Attempt at a Solution



I know that the electric field for r < a is E = (rho*r)/(3*epsilon_0).

And the electric field for r > b is E = (rho*b^3)/(3*epsilon_0*r^2).
Actually, neither of those answers is correct. For one thing, where's q? And the first answer shouldn't depend on ρ.
But I can't seem to figure out the electric field for a < r < b. I've tried using the same method, but I get really confused. I'm thinking that it might just be zero, but I'm not sure.

Any suggestions would be greatly appreciated!
Show us what you've tried so we can see where you're getting confused.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
6
Views
2K
Replies
23
Views
5K
Replies
11
Views
2K
  • · Replies 12 ·
Replies
12
Views
8K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
782
  • · Replies 16 ·
Replies
16
Views
2K