Calculating Electron Acceleration Potential

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SUMMARY

The discussion focuses on calculating the potential difference required to accelerate an electron from rest to achieve a wavelength of 0.154 nm. The correct formula used is eV = hc / λ, leading to a calculated potential of 8072V. Participants identified a typo in the original problem statement, clarifying that the denominator should be λ instead of mv, emphasizing the importance of accurate variable representation in physics equations.

PREREQUISITES
  • Understanding of electron acceleration and potential difference
  • Familiarity with the equation eV = hc / λ
  • Basic knowledge of quantum mechanics and wave-particle duality
  • Proficiency in unit conversions, particularly nanometers to meters
NEXT STEPS
  • Study the derivation of the equation eV = hc / λ
  • Explore the implications of electron wavelength in quantum mechanics
  • Learn about potential difference and its applications in particle physics
  • Investigate common typographical errors in physics textbooks and their impact on problem-solving
USEFUL FOR

Students in physics, educators teaching quantum mechanics, and anyone involved in particle acceleration and wave-particle duality concepts.

gxc9800
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Homework Statement


Calculate the potential difference required to accelerate electron from rest to acquire wavelength of 0.154nm

Homework Equations

The Attempt at a Solution


eV = hc / λ
(1.6x10^-9) (V) = (6.63x10^-34)(3x10^8)/ 0.154x10^-9
V = 8072V ...
here's the sample ans :
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It's about an electron. There is no speed of light in the formula for momentum of the electron.
You are mixing up things.

I think there is a typo in the book. The denominator in the last formula should be ## \lambda ## and not mv.
 
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It is a typo, but they still used lambda where you would expect them to plug in (incorrectly) v.
 

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