How Is Electric Potential Difference Calculated in a TV Tube?

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SUMMARY

The calculation of electric potential difference in a TV tube involves determining the velocity of electrons accelerated from rest. Using the de Broglie wavelength formula, λ=h/mv, and the kinetic energy equation, ∆E_K=q∆V, the potential difference is calculated. The correct value for the electric potential difference is approximately 1.51×10^4 V, assuming the wavelength is accurately given as 10×10^(-11) m. Discrepancies in the wavelength value lead to different potential difference results, emphasizing the importance of precise data in calculations.

PREREQUISITES
  • Understanding of de Broglie wavelength (λ=h/mv)
  • Familiarity with kinetic energy equations (∆E_K=q∆V)
  • Knowledge of electron charge (e=1.6×10^(-19) C)
  • Basic principles of electron acceleration in electric fields
NEXT STEPS
  • Review the de Broglie wavelength concept and its applications in particle physics
  • Study the relationship between kinetic energy and electric potential difference
  • Explore the implications of electron acceleration in CRT technology
  • Investigate common errors in physics calculations and how to avoid them
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and quantum mechanics, as well as educators looking to clarify concepts related to electric potential difference in electron dynamics.

  • #31
Physics345 said:
4.4x10^-67/2[(9.11x10^-31)(1.6x10^-17)]
4.4x10^-67/2.92x10-47
=1.5x10^-18
P.D= 1.5x10^-18 x (1/(10x10^-11)^2)
=1.5x10^-18 x (1/1x10-20)
=1.5x10^-18(1x10^20)
=1.5x10^2
=150
that's why i an of the opinion that wavelength must be corrected
 
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  • #32
drvrm said:
thats why i an of the opinion that wavelength must be corrected
What do you mean? by "I an of the opinion must be correct"
 
  • #33
Physics345 said:
What do you mean? by "I an of the opinion must be correct"

I am referring to your teacher's reply which you wrote earlier that the P.D. should be !0^4 order ...that's why i am saying that unless wavelength gets changed to lower value the P.D. can not increase.. if you try only !0^-11 as wavelength you can get that order of P.D.
 
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  • #34
so basically, the wavelength won't allow for any higher P.D. than we are getting here. Basically if I list the work we just did it should explain to him why my answer is correct?
 
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  • #35
This is really silly though, I shouldn't have to explain this to him. He should of done the math him self and came to the conclusion my answer was correct. Praise be to drvrm! I appreciate you helping me teach the teacher. This feels great =) I asked for extra marks for the explanation.
 
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