Calculating Elongation of an Orange Spring

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SUMMARY

The elongation of an orange spring with a spring constant of 14,000 g/s² when a 200-g mass is attached is calculated using the formula elongation = hanging mass * gravity / spring constant. By substituting the values, elongation equals 200 * 980 / 14,000, resulting in a stretch of 14 cm. This calculation confirms that the spring will extend by 14 cm from its original unstretched position, validating the accuracy of the method used.

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brayrbob
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An orange spring has a spring constant of 14,000 g/s^2. How much should it stretch if a 200-g mass is attached from it?
I took the equation hanging mass * gravity=spring constant * elongation and turned it around for solving elongation
elongation = 200 * 980/14,000 = 14cm and I'm checking to see if this is the right answer.
 
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Looks correct to me.
 


Your calculation is correct! The equation you used, elongation = hanging mass * gravity / spring constant, is the correct formula for calculating elongation of a spring. By plugging in the given values, you correctly determined that the orange spring should stretch by 14cm when a 200-g mass is attached to it. This means that the spring will increase in length by 14cm from its original unstretched position. Great job!
 

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