Calculating Energy (capcitor study)

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Discussion Overview

The discussion revolves around the calculation of energy stored in a capacitor and the energy lost when the voltage across it is reduced. Participants are examining the energy calculations for a 100 microfarad capacitor initially charged to 100 volts and then discharged to 50 volts, with a resistor placed across its terminals. The focus is on understanding discrepancies between personal calculations and a reference book's answer.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant calculates the initial energy using the formula w = 1/2 CV^2, yielding 0.5 J for the initial voltage of 100 V.
  • The same participant notes that the book states the energy is 0.25 J, leading to confusion about the origin of the number 25 in the book's calculation.
  • Another participant agrees that the final energy should be computed as the difference between the initial and final energies, but expresses concern about the initial computation of energy.
  • A different participant suggests that the book's answer may not align with the question posed and questions whether the original question was copied correctly.
  • There is a consensus that the calculation for energy at half voltage does not seem to relate to the book's number, prompting a suggestion to consult the professor for clarification.

Areas of Agreement / Disagreement

Participants generally agree on the method of calculating energy loss as the difference between initial and final energies. However, there is disagreement regarding the correctness of the initial energy calculation and the reference book's answer, which remains unresolved.

Contextual Notes

Participants express uncertainty about the values used in the book's calculations and the potential for misinterpretation of the original question. The discussion highlights the need for clarity in the problem statement and the calculations involved.

Alphonse
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Study guide asked/stated: A 100 microF capacitor has 100 V across it terminals, A 100 ohm
resistor is placed across these terminals. How much energy is lost when the voltage is dropped to 50V?

I answered with w= 1/2 CV^2, 1/2*100*10E-6*100^2
= .5 J
Book says w = 25 * 10-6 * 10^4.
= .25 J

(next step is to calculate energy at 50V). Where did the 25 come from?

Hope this is the right forum (and not already asked and answered).
 
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Alphonse said:
Study guide asked/stated: A 100 microF capacitor has 100 V across it terminals, A 100 ohm
resistor is placed across these terminals. How much energy is lost when the voltage is dropped to 50V?

I answered with w= 1/2 CV^2, 1/2*100*10E-6*100^2
= .5 J
Book says w = 25 * 10-6 * 10^4.
= .25 J

(next step is to calculate energy at 50V). Where did the 25 come from?

Hope this is the right forum (and not already asked and answered).

The delta energy should be a subtraction... final E versus initial E. Does that help?
 
Beckeman, thanks for your reply. I agree the final answer is computed from the difference
of the two. My problem is in initial computation of energy.

Alphonse
 
Alphonse said:
Study guide asked/stated: A 100 microF capacitor has 100 V across it terminals, A 100 ohm
resistor is placed across these terminals. How much energy is lost when the voltage is dropped to 50V?

I answered with w= 1/2 CV^2, 1/2*100*10E-6*100^2
= .5 J
Book says w = 25 * 10-6 * 10^4.
= .25 J

(next step is to calculate energy at 50V). Where did the 25 come from?

Hope this is the right forum (and not already asked and answered).

I agree that the book's answer appears not to be what the question is asking. Any chance you copied the question down wrong above? Your calculation looks correct to me, and the number you will get at half voltage does not seem to be related to the book's number. Maybe ask the prof?
 

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