Calculating Energy Needs: Converting KWh to g/year in a Typical Home

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SUMMARY

A typical home consumes approximately 1600 kWh of energy monthly, equating to 19,200 kWh annually. To determine the mass that must be converted to energy from a nuclear reaction to meet this energy requirement, the equation E=mc² is utilized. Given that 1 kWh equals 3.6 million joules, the necessary mass can be calculated using the speed of light, c, which is 2.9979 x 108 m/s. This calculation reveals the relationship between energy consumption and mass-energy equivalence.

PREREQUISITES
  • Understanding of energy units (kWh and joules)
  • Familiarity with Einstein's mass-energy equivalence (E=mc²)
  • Knowledge of the speed of light (c = 2.9979 x 108 m/s)
  • Basic arithmetic and algebra skills for calculations
NEXT STEPS
  • Calculate the annual energy consumption in joules for different household sizes
  • Explore the implications of mass-energy conversion in nuclear physics
  • Research the efficiency of nuclear energy compared to other energy sources
  • Learn about the environmental impact of nuclear energy production
USEFUL FOR

Students in physics, energy analysts, homeowners interested in energy consumption, and anyone studying nuclear energy principles.

PhysicFailure
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A typical home uses approximately 1600 kWh of energy per month.If the energy came from a nuclear reaction, what mass would have to be converted to energy per year to meet the energy needs of the home? (in g/year)

I don't know how to do this problem :S
 
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the things you need to know to solve the problem are:

a watt has units: J/s

E(in joules) [tex]= mc^{2}[/tex] <---this is the equation you should use to calculate how much mass is required to be converted.

[tex]c = 2.9979 x 10^{8}[/tex]m/s <---speed of light.
 
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