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Assume we have a deuterium-tritium reaction. The energy released is 17.6 MeV. I know from solved examples that neutrons carry 14.1 MeV and Helium carries 3.5 MeV. How do I calculate these numbers (14.1 MeV and 3.5 MeV)?

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In summary, the formula for calculating the energy of a deuterium-tritium reaction is E = (m<sub>d</sub> + m<sub>t</sub> - m<sub>p</sub> - m<sub>n</sub>)c<sup>2</sup>, where E is the energy, m<sub>d</sub> is the mass of deuterium, m<sub>t</sub> is the mass of tritium, m<sub>p</sub> is the mass of a proton, m<sub>n</sub> is the mass of a neutron, and c is the speed of light. The mass of deuterium and tritium can be determined by using the

- #1

- 22

- 0

Assume we have a deuterium-tritium reaction. The energy released is 17.6 MeV. I know from solved examples that neutrons carry 14.1 MeV and Helium carries 3.5 MeV. How do I calculate these numbers (14.1 MeV and 3.5 MeV)?

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Looks like the energy is shared between the products inversely proportional to their mass

The formula for calculating the energy of a deuterium-tritium reaction is E = (m_{d} + m_{t} - m_{p} - m_{n})c^{2}, where E is the energy, m_{d} is the mass of deuterium, m_{t} is the mass of tritium, m_{p} is the mass of a proton, m_{n} is the mass of a neutron, and c is the speed of light.

The mass of deuterium and tritium can be determined by using the atomic mass of each element, which can be found on the periodic table. Deuterium has a mass of 2.014 atomic mass units (amu) and tritium has a mass of 3.016 amu.

The speed of light used in the calculation is the standard speed of light, which is approximately 299,792,458 meters per second.

The energy of a deuterium-tritium reaction is typically measured in joules (J) or electron volts (eV). One joule is equal to 6.242x10^{18} electron volts.

Yes, the energy of a reaction can be calculated using any elements that undergo fusion. However, the mass and atomic properties of each element will need to be taken into account in the calculation.

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