Calculating Energy of Deuterium-Tritium Reaction

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    Nuclear Reactions
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SUMMARY

The deuterium-tritium reaction releases 17.6 MeV of energy, with neutrons carrying 14.1 MeV and helium nuclei carrying 3.5 MeV. The calculation of these energy values is based on the principles of energy and momentum conservation. In the center of mass frame, the energy distribution between the neutron and helium is inversely proportional to their masses, ensuring that both products maintain equal and opposite momentum. This method provides a clear framework for understanding energy distribution in nuclear reactions.

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Dr. Octavious
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Hello all,

Assume we have a deuterium-tritium reaction. The energy released is 17.6 MeV. I know from solved examples that neutrons carry 14.1 MeV and Helium carries 3.5 MeV. How do I calculate these numbers (14.1 MeV and 3.5 MeV)?
 
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Energy and momentum conservation. Assume that the lab frame is the center of mass frame, and then see how to distribute the energy to give both the same momentum (just with opposite sign).
 
Looks like the energy is shared between the products inversely proportional to their mass
 

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