Calculating Energy Stored in Series and Parallel Capacitor Circuits

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Homework Help Overview

The discussion revolves around calculating the energy stored in two circuits with capacitors, one configured in series and the other in parallel, using a 10-volt battery. The capacitors involved are 5.3 microfarads and 2.4 microfarads.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of finding equivalent capacitance and the relationship between charge and capacitance in series and parallel configurations. Questions arise about how to determine the total charge stored on the capacitors.

Discussion Status

Participants are exploring the differences in charge distribution between series and parallel capacitor configurations. Some guidance has been offered regarding the charge on capacitors in series and parallel, but no consensus has been reached on the approach to calculating energy stored.

Contextual Notes

There is a noted lack of visual aids, such as circuit diagrams, which may be affecting the clarity of the discussion. Participants are also referencing external resources for further clarification.

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Homework Statement


you have a 10 volt battery and two separate circuits with capacitors. One circuit has the capacitors in series, the other has the capacitors in parallel. Find the energy stored

one capacitor is 5.3 microfarads
the other capacitor is 2.4 microfarads

Homework Equations


energy = (Q^2)/(2C)


The Attempt at a Solution


after finding the equivalent capacitance, would you just add the total amount of charge stored on each capacitor to find charge?
 
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tough to say without the picture...

if two capacitors are in series, then each capacitor has the same charge... and the equivalent capacitor has that same charge...

if two capacitors are in parallel, then the charge on the equiv. capacitance is the sum of the charges on each capacitor.
 
learningphysics said:
tough to say without the picture...

if two capacitors are in series, then each capacitor has the same charge... and the equivalent capacitor has that same charge...

if two capacitors are in parallel, then the charge on the equiv. capacitance is the sum of the charges on each capacitor.

so for the series capacitor, which holds the same amt charge on each capacitor, you wouldn't add the two charges on each capacitor together to get Q?
 
boogiebear said:
so for the series capacitor, which holds the same amt charge on each capacitor, you wouldn't add the two charges on each capacitor together to get Q?

no. the total charge is the same as the charge on each capacitor. have a look at this:

http://www.ac.wwu.edu/~vawter/PhysicsNet/Topics/Capacitors/ParSeriesCap.html
 
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